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3 years ago

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If 3.0g of H20 actually forms what is the percentage yield

1 answer:

Sati [7]3 years ago

5 0

Percent yield is expressed as the ratio of the actual yield and the theoretical yield of the reaction multiplied by 100 to get the percent value. The actual yield is usually given in a problem. The theoretical yield is calculated from the reaction. For this problem, it cannot be solved since we cannot obtain the theoretical yield.

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Naturally occurring europium (Eu) consists of two isotopes was a mass of 151 and 153 . Europium-151 has an abundance of 48.03% a

Minchanka [31]

Answer:

151.94 u

Explanation:

The atomic mass of Eu is the <em>weighted average</em> of the atomic masses of its isotopes.

We multiply the atomic mass of each isotope by a number representing its relative importance (i.e., its <em>percent abundance</em>).

The atomic masses of Eu-151 and Eu-153 are 150.92 u and 152.92 u, respectively.

Set up a table for easy calculation.

0.4803 × 150.92 u = 72.472 u

0.5197 × 152.92 u = <u> 79.473 u </u>

TOTAL = 151.94 u

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3 years ago

Read 2 more answers

Balance the following reaction.<br> C₂H6+ Cl2<br> C2H4Cl2 +<br> HCI

julsineya [31]

Answer:

C2H6 + 2 Cl2 = C2H4Cl2 + 2 HCl

Explanation:

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3 years ago

How many oxygen atoms are there in 5 molecules of Al2(SO4)?

timama [110]

Answer:

There are two aluminum ions and three sulfate ions; or two aluminum, three sulfur, and twelve oxygen atoms.

Explanation:

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3 years ago

How many moles are there in 6.33x10^23 molecules of NH3?

nadezda [96]

About 1.051 moles (depends on how u round it)

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2 years ago

Cobalt-60 is a strong gamma emitter that has a half- life of 5.26 yr. The co balt-60 in a radiotherapy unit must be replaced whe

Alenkasestr [34]

<u>Answer:</u> The sample of Cobalt-60 isotope must be replaced in January 2027

<u>Explanation:</u>

The equation used to calculate rate constant from given half life for first order kinetics:

$t_{1/2}=\frac{0.693}{k}$

where,

$t_{1/2}$ = half life of the reaction = 5.26 years

Putting values in above equation, we get:

$k=\frac{0.693}{5.26yrs}=0.132yrs^{-1}$

Rate law expression for first order kinetics is given by the equation:

$k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}$

where,

k = rate constant = $0.132yr^{-1}$

t = time taken for decay process = ? yr

$[A_o]$ = initial amount of the sample = 100 grams

[A] = amount left after decay process = (100 - 75) = 25 grams

Putting values in above equation, we get:

$0.132=\frac{2.303}{t}\log\frac{100}{25}\\\\t=10.5yrs$

The original sample was purchased in June 2016

As, June is the 6th month of the year, which means the time period will be $2016+\frac{6}{12}=2016.5$

Adding the time in the original time period, we get:

$2016.5+10.5=2027$

Hence, the sample of Cobalt-60 isotope must be replaced in January 2027

3 0

3 years ago