In a parallel circuit, both bulbs are connected directly to the power supply
or battery. As long as the power supply is capable of running both of them,
neither bulb is aware of the other's presence. If one bulb fails 'open', the
other bulb doesn't change at all. The voltage across it, the current through it,
its resistance, and its brightness,all remain exactly as they were before.
Answer:
1)a. It is constant the whole time the ball is in free-fall.
2)b. = 14 m/s
3) e. = 19.6 m/s
Explanation:
1) given that the only force acting on the ball is gravity, gravity acts along the vertical axis. Since no other force acts on the ball then the horizontal velocity will remain constant all through the flight since there is no horizontal force acting on the ball.
2) speed = distance/time
horizontal distance = 56m
Time = 4 seconds
Speed = 56m/4s = 14m/s
3) acceleration due to gravity g = 9.8m/s^2
Initial vertical velocity = u
Final vertical velocity = v = -u
Using the law of motion;
v = u + at
a = acceleration = -g = -9.8m/s^2
t = time of flight = 4
Substituting the values;
-u = u - 4(9.8)
-2u = -4(9.8)
u = -4(9.8)/-2
u = 2(9.8) = 19.6 m/s
Initial vertical velocity = u = 19.6 m/s
An object moving in a circle wants to move in a straight line.
The motion of an object is tangent to the circle.
Tangential speed remains constant for an object with uniform circular motion.
Only the direction of the object changes, which means velocity is changing and the object is accelerating
Answer:
B
Explanation:
The correct answer is Amplitude.
The train's average speed during that 24.8 seconds is
(1/2) (4.82 m/s + 7.09 m/s)
= (1/2) (11.91 m/s)
= 5.955 m/s .
Traveling at an average speed of 5.955 m/s for 24.8 sec,
it covers
(5.955 m/s) x (24.8 sec) = 147.68 meters .