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nikklg [1K]
3 years ago
14

Nitrogen (n) atomic number = _____ atomic mass = _____ number of protons = _____ number of neutrons = _____ number of electrons

= _____ number of electrons in the valence shell: _____
Chemistry
1 answer:
inessss [21]3 years ago
7 0
Nitrogen, Periodic abbreviation= N
Atomic Number: 7, as it has 7 protons
Atomic Mass: 14.007, so around 7 protons and 7 neutrons depending on isotope type
# Protons: 7
# Neutrons: 7
# Electrons: 7, usually, but not always, equal to # of Protons
Valence Electrons: 5, as with 7 electrons total, 2 would fill the first valence shell, leaving 5 in the valence, or outermost, shell.
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Proteins have many functions in the cell membrane. Which function is NOT related to a protein?a. transportb. membrane fluidityc.
kirill115 [55]

The function that is NOT related to a protein is:

Membane fluidity.

Membrane fluidity is not related to a protein function because membrane fluidity is a function of lipids not proteins.

Transport and all other options are involved in functions of protein.

5 0
1 year ago
Be sure to answer all parts. Dimercaprol (HSCH2CHSHCH2OH) was developed during World War I as an antidote to arsenic-based poiso
Sauron [17]

<u>Answer:</u>

<u>For A:</u> The number of arsenic atoms are 3.4\times 10^{21}

<u>For B:</u> The percent composition of mercury, thallium and chromium in their complexes are 61.76 %, 62.2 % and 29.51 % respectively.

<u>Explanation:</u>

  • <u>For A:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of dimercaprol = 696 mg = 0.696 g    (Conversion factor:  1 g = 1000 mg)

Molar mass of dimercaprol = 124.21 g/mol

Putting values in above equation, we get:

\text{Moles of dimercaprol}=\frac{0.696g}{124.21g/mol}=0.0056mol

According to mole concept:

1 mole of a compound contains 6.022\times 10^{23} number of molecules.

So, 0.0056 moles of dimercaprol will contain 0.0056\times 6.022\times 10^{23}=3.4\times 10^{21} number of molecules.

As, 1 molecule of dimercaprol binds with 1 atom of Arsenic

So, 3.4\times 10^{21} number of dimercaprol molecules will bind with = 1\times 3.4\times 10^{21}=3.4\times 10^{21} number of arsenic atoms

Hence, the number of arsenic atoms are 3.4\times 10^{21}

  • <u>For B:</u>

We know that:

Molar mass of dimercaprol = 124.21 g/mol

Molar mass of mercury = 200.59 g/mol

Molar mass of thallium = 204.38 g/mol

Molar mass of chromium = 51.99 g/mol

Also, 1 molecule of dimercaprol binds with 1 metal atom.

To calculate the percentage composition of metal in a complex, we use the equation:

\%\text{ composition of metal}=\frac{\text{Mass of metal}}{\text{Mass of complex}}\times 100     ......(1)

  • <u>For mercury:</u>

Mass of Hg-complex = (200.59 + 124.21) = 324.8 g

Mass of mercury = 200.59 g

Putting values in equation 1, we get:

\%\text{ composition of mercury}=\frac{200.59g}{324.8g}\times 100=61.76\%

  • <u>For thallium:</u>

Mass of Tl-complex = (204.38 + 124.21) = 328.59 g

Mass of thallium = 204.38 g

Putting values in equation 1, we get:

\%\text{ composition of thallium}=\frac{204.38g}{328.59g}\times 100=62.2\%

  • <u>For chromium:</u>

Mass of Cr-complex = (51.99 + 124.21) = 176.2 g

Mass of chromium = 51.99 g

Putting values in equation 1, we get:

\%\text{ composition of chromium}=\frac{51.99g}{176.2g}\times 100=29.51\%

Hence, the percent composition of mercury, thallium and chromium in their complexes are 61.76 %, 62.2 % and 29.51 % respectively.

8 0
3 years ago
Which statement about fission is correct?
sashaice [31]
Answer chocies .......................                                                                  
6 0
3 years ago
Read 2 more answers
Determine the hydroxide ion concentration in a solution that is 0.018 m naoh.
nydimaria [60]
As we know, NaOH is a strong Base and completely dissociates in water as given below,

                            NaOH + H₂O    →   Na⁺ ₍aq₎  +  OH⁻ ₍aq₎

So, the concentration of OH⁻ Ions will be the same as that the concentration of NaOH i.e. 0.018 M.
So,
                                     [OH⁻]  =  0.018 M
5 0
3 years ago
The relative abundances of the stable isotopes of the elements are not entirely constant. For example, in some geologic samples
Mrac [35]

<u>Answer:</u> The other isotope is _{37}^{87}\textrm{Rb}

<u>Explanation:</u>

Beta decay is defined as the decay process in which a neutron gets converted to a proton and an electron.

In this decay process, beta particle is emitted. The emitted particle carries a charge of -1 units and has a mass of 0 units. The released beta particle is also known as electron.

The general equation for the beta decay process follows:

_Z^A\textrm{X}\rightarrow _{Z+1}^A\textrm{Y}+_{-1}^0\beta

The chemical equation for the beta decay of an isotope that produces Sr-87 isotope follows:

_{37}^{87}\textrm{Rb}\rightarrow _{38}^{87}\textrm{Sr}+_{-1}^0\beta

The isotope that undergoes beta decay to form Strontium-87 isotope is Rubidium-87

Hence, the other isotope is _{37}^{87}\textrm{Rb}

4 0
3 years ago
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