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nikklg [1K]
3 years ago
14

Nitrogen (n) atomic number = _____ atomic mass = _____ number of protons = _____ number of neutrons = _____ number of electrons

= _____ number of electrons in the valence shell: _____
Chemistry
1 answer:
inessss [21]3 years ago
7 0
Nitrogen, Periodic abbreviation= N
Atomic Number: 7, as it has 7 protons
Atomic Mass: 14.007, so around 7 protons and 7 neutrons depending on isotope type
# Protons: 7
# Neutrons: 7
# Electrons: 7, usually, but not always, equal to # of Protons
Valence Electrons: 5, as with 7 electrons total, 2 would fill the first valence shell, leaving 5 in the valence, or outermost, shell.
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Explanation:

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Which is an "enumerated" power of Congress?
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Ammonium perchlorate NH4ClO4 is a powerful solid rocket fuel, used in the Space Shuttle boosters. It decomposes into nitrogen N2
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Answer: 0.055 moles of O_2 are produced by the reaction of 0.055 mol of ammonium perchlorate.

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According to stoichiometry :

2 moles of NH_4ClO_4 produce = 2 moles of O_2

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7 0
3 years ago
Uranium-238 decays to lead-206 with a half-life of 4.5 x 109 yr. Determine how much uranium-238 decays in milligrams (to three s
Mamont248 [21]

Answer:

2.15 mg of uranium-238 decays

Explanation:

For decay of radioactive nuclide-

                        N=N_{0}.(\frac{1}{2})^{\frac{t}{t_{\frac{1}{2}}}}

where N is amount of radioactive nuclide after t time, N_{0} is initial amount of radioactive nuclide and t_{\frac{1}{2}} is half life of radioactive nuclide

Here N_{0}=4.60 mg, t=4.1\times 10^{9}yr and t_{\frac{1}{2}}=4.5\times 10^{9}yr

So,N=(4.60mg)\times (\frac{1}{2})^{\frac{4.1\times 10^{9}}{4.5\times 10^{9}}}

so, N = 2.446 mg

mass of uranium-238 decays = (4.60-2.446) mg = 2.15 mg

3 0
3 years ago
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