Se midió el pH de una muestra del agua de lluvia en la ciudad de México, y se obtuvo un valor de 3.5 Calcula la [H+] en dicha mu
1 answer:
Answer:
Explanation:
¡Hola!
En este caso, dado que el pH de una solución se entiende como el potencial de los iones hidrógeno en la misma, es posible recordar la ecuación que se usa para calcularlo:
De este modo, al conocer el pH, se resuelve para la concentración de iones hidrógeno como se muestra a continuación:
Así, reemplazamos el pH para obtener:
¡Saludos!
You might be interested in
Explanation:
1) Initial mass of the Cesium-137== 180 mg
Mass of Cesium after time t = N
Formula used :
Half life of the cesium-137 = = initial mass of isotope
N = mass of the parent isotope left after the time, (t)
= half life of the isotope
= rate constant
Now put all the given values in this formula, we get
Mass that remains after t years.
Therefore, the parent isotope remain after one half life will be, 100 grams.
2)
t = 70 years
N = 35.73 mg
35.73 mg of cesium-137 will remain after 70 years.
3)
N = 1 mg
t = ?
t = 224.80 years ≈ 225 years
After 225 years only 1 mg of cesium-137 will remain.
5.512 litres is the volume of 15.2 grams of sulphur dioxide gas at STP.
Explanation:
Data given:
mass of sulphur dioxide = 15.2 grams
conditions is at STP whech means volume = 22.4 litres
atomic mass of sulphur dioxide = 64.06 grams/mole
Number of moles is calculated as:
number of moles =
Putting the values in the equation:
number of moles =
= 0.23 moles
Assuming that sulphur dioxide behaves as an ideal gas, we can calculate the volume as:
When 1 mole of sulphur dioxide occupies 22.4 litres at STP
Then 0.23 moles of sulphur dioxide occupies 22.4 x 0.23
= 5.152 litres is the volume.