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SOVA2 [1]
3 years ago
13

Whats the word for when "velocity equals 0 and direction changes" Its 14 letters, and I have _ _ _ _ i _ _ _ _ _ h_ i _ _ t

Physics
1 answer:
alisha [4.7K]3 years ago
6 0

Answer:

Maximum Height

Explanation:

The maximum height is the highest point reached by a projected body. At this point, final velocity, v of the body is equal to 0; because upward motion is at its peak and the body start to fall again.

Hence, final velocity v is always 0 at this maximum point and the direction of motion changes from upward to downward.

Final velocity at this maximum height is zero because of the directional change experied by the object and the fact that upward motion of the body terminates at this point.

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A laser pulse with wavelength 532 nm contains 3.85 mj of energy. how many photons are in the laser pulse?
erastovalidia [21]

Answer:<em> </em><em>1.04 × 10¹⁶ photons</em>


Explanation:


1) Data:

  • E = 3.85mJj (mili joules) = 3.85×10⁻³ J
  • λ = 532 nm = 532 × 10⁻⁹ m
  • number of photons ?

2) Physical principles

a) The energy of a photon is given by the equation E = hν.

Where:

  • h is Planck's constant 6.62607004 × 10⁻³⁴ J×s
  • ν is the freguency of the light

b) The wavelength, λ, and the frequency, are related by the equation:

  • ν = c / λ, where c is the speed of light at vacuum, approximately 3.0 × 10⁸ m/s

3) Solution:

  • ν = c / λ = 3.0 × 10⁸ m/s / (538 nm) × 10⁹ nm/m = 5.576×10¹⁴ Hz

  • E = hν = 6.62607004 × 10⁻³⁴ J×s s × 5.576×10¹⁴ Hz = 3.69 × 10 ⁻¹⁹ J

  • Divide the total energy by the energy of one photon to find the number of photons:

         3.85×10⁻³ J / 3.69 × 10 ⁻¹⁹ J-photon = 1.04 × 10¹⁶ photons ← answer


4 0
3 years ago
Read 2 more answers
It takes 500 W of power to move an object 96 m in 12 s. What force is being applied to the object?
agasfer [191]

Answer: 125/24 N

Explanation:

The work can be calculated with W = Fs

Where W = work

F = force

and s = displacement

Let's set up the equation:

500w = F * 96m

\frac{500}{96} = 125/24 or roughly 5.2 N of force

4 0
3 years ago
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A horizontal pipe 18.0 cm in diameter has a smooth reduction to a pipe 9.00 cm in diameter. If the pressure of the water in the
Rzqust [24]

Answer:

The rate of flow of water is 71.28 kg/s

Solution:

As per the question:

Diameter, d = 18.0 cm

Diameter, d' = 9.0 cm

Pressure in larger pipe, P = 9.40\times 10^{4}\ Pa

Pressure in the smaller pipe, P' = 2.80\times 10^{4}\ Pa

Now,

To calculate the rate of flow of water:

We know that:

Av = A'v'

where

A = Cross sectional area of larger pipe

A' = Cross sectional area of larger pipe

v = velocity of water in larger pipe

v' = velocity of water in larger pipe

Thus

\pi \frac{d^{2}}{4}v = \pi \frac{d'^{2}}{4}v'

18^{2}v = 9^v'

v' = 4v

Now,

By using Bernoulli's eqn:

P + \frac{1}{2}\rho v^{2} + \rho gh = P' + \frac{1}{2}\rho v'^{2} + \rho gh'

where

h = h'

\rho = 10^{3}\ kg/m^{3}

9.40\times 10^{4} + \frac{1}{2}\rho v^{2} = 2.80\times 10^{4} + \frac{1}{2}\rho (4v)^{2}

6.6\times 10^{4}  = \frac{1}{2}\rho 15v^{2}

v = \sqrt{\frac{2\times 6.6\times 10^{4}}{15\times 10^{3}}} = 8.8\ m/s

Now, the rate of flow is given by:

\frac{dm}{dt} = \frac{d}{dt}\rho Al = \rho Av

\frac{dm}{dt} = 10^{3}\times \pi (\frac{18}{2}\times 10^{- 2})^{2}\times 8.8 = 71.28\ kg/s

3 0
3 years ago
Read 2 more answers
Does the plane of the ecliptic coincide with the plane of the equator? explain.
melisa1 [442]
<span>no it doesn't. one way to think of it is that the tropic of capricorn is the furthest south the sun's path goes, and the tropic of cancer is the northern most line that the sun traces out. since neither the tropic of capriforn nor the tropic of cancer are on the equator, the sun must be tracing out a different line and hence be on a different plane. also, if the sun was on the same plane as the equator, then we wouldn't have seasons.</span>
3 0
3 years ago
7) A meter stick is being balanced on a triangular piece of wood, with two blocks hanging off of
Airida [17]

Explanation:

a) It will weigh less because of its distance from the block.

b) torque = W1×d1 = (10N)(0.25m) = 2.5 N-m

c) torque = W2×d2 = W2×(0.50m)

d) W2×d2 = W1×d1

W2 = (d1/d2)W1

= 5 N

8 0
3 years ago
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