Answer:<em> </em><em>1.04 × 10¹⁶ photons</em>
Explanation:
1) Data:
- E = 3.85mJj (mili joules) = 3.85×10⁻³ J
- λ = 532 nm = 532 × 10⁻⁹ m
2) Physical principles
a) The energy of a photon is given by the equation E = hν.
Where:
- h is Planck's constant 6.62607004 × 10⁻³⁴ J×s
- ν is the freguency of the light
b) The wavelength, λ, and the frequency, are related by the equation:
- ν = c / λ, where c is the speed of light at vacuum, approximately 3.0 × 10⁸ m/s
3) Solution:
- ν = c / λ = 3.0 × 10⁸ m/s / (538 nm) × 10⁹ nm/m = 5.576×10¹⁴ Hz
- E = hν = 6.62607004 × 10⁻³⁴ J×s s × 5.576×10¹⁴ Hz = 3.69 × 10 ⁻¹⁹ J
- Divide the total energy by the energy of one photon to find the number of photons:
3.85×10⁻³ J / 3.69 × 10 ⁻¹⁹ J-photon = 1.04 × 10¹⁶ photons ← answer
Answer: 125/24 N
Explanation:
The work can be calculated with W = Fs
Where W = work
F = force
and s = displacement
Let's set up the equation:
500w = F * 96m
= 125/24 or roughly 5.2 N of force
Answer:
The rate of flow of water is 71.28 kg/s
Solution:
As per the question:
Diameter, d = 18.0 cm
Diameter, d' = 9.0 cm
Pressure in larger pipe, P = 
Pressure in the smaller pipe, P' = 
Now,
To calculate the rate of flow of water:
We know that:
Av = A'v'
where
A = Cross sectional area of larger pipe
A' = Cross sectional area of larger pipe
v = velocity of water in larger pipe
v' = velocity of water in larger pipe
Thus

v' = 4v
Now,
By using Bernoulli's eqn:

where
h = h'




Now, the rate of flow is given by:


<span>no it doesn't.
one way to think of it is that the tropic of capricorn is the furthest south the sun's path goes, and the tropic of cancer is the northern most line that the sun traces out.
since neither the tropic of capriforn nor the tropic of cancer are on the equator, the sun must be tracing out a different line and hence be on a different plane.
also, if the sun was on the same plane as the equator, then we wouldn't have seasons.</span>
Explanation:
a) It will weigh less because of its distance from the block.
b) torque = W1×d1 = (10N)(0.25m) = 2.5 N-m
c) torque = W2×d2 = W2×(0.50m)
d) W2×d2 = W1×d1
W2 = (d1/d2)W1
= 5 N