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777dan777 [17]
3 years ago
14

An axe used to split wood is driven into a piece of wood for an input distance of 0.03. If the mechanical advantage of the axe i

s 0.85, how far apart ( output distance ) is the wood split? ( Round to two decimal places. ) ( Ex: 1.28)
Physics
1 answer:
9966 [12]3 years ago
6 0

Answer:

.9 im guessing

Explanation:

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Why is the weight of the ruler not include in the calculation of moment?​
Feliz [49]

Answer:

Since the distance between the pivot and its weight is zero, the moment of its weight about the pivot (= weight × 0) is zero. Hence, the weight of the ruler can be ignored.

Hope this helps:)

3 0
3 years ago
If you decrease the frequency of a vibrating object to one fourth ,its period becomes
shepuryov [24]
It's period would become D
4 0
3 years ago
At a country music festival, a band is playing at the end of a crowded
Dominik [7]

Answer:

2270 full wavelengths.

Explanation:

The wavelength \lambda of the sound wave (assuming sound speed of  v= 343m/s) is

\lambda = \dfrac{v}{f} = \dfrac{343m/s}{400hz}

\lambda = 0.8575m.

Now, assuming the distance to the last row is 1947m, the number n of wavelengths that fit into this distance are

n = \dfrac{1947m}{0.8575m}

n= 2270.55

which is 2270 full wavelengths.

Hence, there are 2270 full wavelengths between the stage and the last row of the crowd.

7 0
3 years ago
A uranium ion and an iron ion are separated by a distance of =61.10 nm. The uranium atom is singly ionized; the iron atom is dou
scoray [572]

Answer:

Explanation:

Charge on uranium ion = charge of a single electron

= 1.6 x 10⁻¹⁹ C

charge on doubly ionised iron atom = charge of 2 electron

= 2 x 1.6 x 10⁻¹⁹ C = 3.2 x 10⁻¹⁹ C

Let the required distance from uranium ion be d .

force on electron at distance d from uranium ion

= 9 x 10⁹ x 1.6 x 10⁻¹⁹ / r²

force on electron at distance 61.10 x 10⁻⁹ - r from iron  ion

= 9 x 10⁹ x 3.2 x 10⁻¹⁹ / (61.10 x 10⁻⁹ - r )²

For equilibrium ,

9 x 10⁹ x 1.6 x 10⁻¹⁹ / r² = 9 x 10⁹ x 3.2 x 10⁻¹⁹ / (61.10 x 10⁻⁹ - r )²

2 d² = (61.10 x 10⁻⁹ - r )²

1.414 r = 61.10 x 10⁻⁹ - r

2.414 r = 61.10 x 10⁻⁹

r = 25.31 nm .

4 0
3 years ago
The velocity of the transverse waves produced by an earthquake is 4.05 km/s, while that of the longitudinal waves is 7.695 km/s.
lora16 [44]

Answer:

x = 600 Km

Explanation:

given,

speed of transverse wave = 4.05 Km/s

speed of longitudinal wave = 7.695 Km/s

difference of the time of arrival of wave = 69.9 s

now,

t₂ - t₁ = 69.9 s

let x be the distance

\dfrac{x}{4.05} - \dfrac{x}{7.695} = 69.9

x = \dfrac{69.9\times 4.05 \times 7.695}{7.695-4.05}

x = 597.645 Km

x = 600 Km

distance of recorder from the site is 600 Km approximately.

4 0
4 years ago
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