Answer:
39
Step-by-step explanation:
Let the three consecutive odd numbers be:
x+2, x+4, x+6.
The sum of the consecutive numbers is 123 i.e
x+2 + (x+4) + (x+6) = 123
x + 2 + x + 4 + x + 6 = 123
3x + 12 = 123
Collect like terms
3x = 123 — 12
3x = 111
Divide both side by the coefficient of x i.e 3
x = 111/3
x = 37
Now let us find the value of the three odd numbers. This is illustrated:
1st : x + 2 = 37 + 2 = 39
2nd : x + 4 = 37 + 4 = 41
3rd : x + 6 = 37 + 6 = 43
The smallest of the three consecutive odd numbers is 39
Answer:
theres no picture.
Step-by-step explanation:
Answer:
838.88
Step-by-step explanation:
Answer:
The other factor is 5x-2
Step-by-step explanation:
Using the factorisation method:
Two numbers that multiply to give -10 and add to give +3:
+5 and -2
![5x^{2} +5x-2x-2](https://tex.z-dn.net/?f=5x%5E%7B2%7D%20%2B5x-2x-2)
![5x(x+1) -2(x+1)](https://tex.z-dn.net/?f=5x%28x%2B1%29%20-2%28x%2B1%29)
![(x+1)(5x-2)](https://tex.z-dn.net/?f=%28x%2B1%29%285x-2%29)
So the other factor is 5x-2
I'm not sure about the second part of the question but I hope you understood how to deal with the first part.