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2 years ago

Which could be an example of an unbalanced force?

Physics

1 answer:

vagabundo [1.1K]2 years ago

5 0

Answer:i think its D

Explanation:

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A steel spur pinion has a module of 2 mm, 17 teeth cut on the 20° full-depth system, and a face width of 20 mm. At a speed of 16

erastovalidia [21]

Answer:

The value of bending stress on the pinion 35.38 M pa

Explanation:

Given data

m = 2 mm

Pressure angle $\phi$ = 20°

No. of teeth T = 17

Face width (b) = 20 mm

Speed N = 1650 rpm

Power = 1200 W

Diameter of the pinion gear

D = m T

D = 2 × 17

D = 34 mm

Velocity of the pinion gear

$V =\pi D( \frac{N}{60} )$

$V = 3.14 (0.034) \frac{(1650)}{60}$

$V = 2.93 \frac{m}{s}$

Form factor for the pinion gear is

Y = 0.303

Now

$K_{v} = \frac{6.1 +0.303}{6.1} = 1.049$

Force on gear tooth

$F = \frac{P}{V}$

$F = \frac{1200}{2.93}$

F = 408.73 N

Now the bending stress is given by the formula

$\sigma = \frac{K_{v} F}{m b y}$

$\sigma = \frac{(1.049)(408.73)}{(0.002)(0.02)(0.303)}$

$\sigma$ = 35.38 M pa

This is the value of bending stress on the pinion

8 0

3 years ago

What is the density of a piece of quartz with a mass of 30g and a volume of 6cm^3

FromTheMoon [43]

Answer:

$\boxed {\boxed {\sf d= 5 \ g/cm^3}}$

Explanation:

Density can be found by dividing the mass by the volume.

$d=\frac{m}{v}$

The mass of the quartz is 30 grams and the volume is 6 cubic centimeters.

$m=30 \ g \\v= 6 \ cm^3$

Substitute the values into the formula.

$d=\frac{30 \ g}{6 \ cm^3}$

Divide.

$d= 5 \ g/cm^3$

The density of this piece of quartz is 5 grams per cubic centimeter.

7 0

3 years ago

In a building with 10.000 cubic feet where the air changes every two hours, what the rate of air change? A. 167.7 cfm B. 83.3 cf

Naya [18.7K]

Answer:

Flow rate of air is given as 83.33 cubic feet per minute

Explanation:

As we know that total volume of the air flow is given as

$V = 10,000 cubic feet$

also we know that total time is

$t = 2 hours = 120 min$

now we have flow rate given as

$Q = \frac{V}{t}$

$Q = \frac{10000}{120}$

$Q = 83.3 cf/m$

3 0

2 years ago

If a fisherman applies a horizontal force with magnitude 47.0 NN to the box and produces an acceleration of magnitude 3.20 m/s2m

musickatia [10]

Answer:

The correct solution is "14.6875 kg".

Explanation:

Given values:

Force,

F = 47.0 N

Acceleration,

a = 3.20 m/s²

Now,

⇒ $Force=Mass\times Acceleration$

or,

⇒ $F=ma$

⇒ $47.0=m\times 3.20$

⇒ $m=\frac{47.0}{3.20}$

⇒ $=14.6875 \ kg$

4 0

2 years ago

Hi guys i need truly help!

lutik1710 [3]

Answer:

1) 327

2) 3

3) 109

------------

now I'm not 100% sure #4-6 are correct, but if 4 is right then 5 and 6 are, too.

4) 1074

5) 1074 + 109t

6) 2382

Explanation:

7 0

3 years ago