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3 years ago

Which table shows data with variability?

2 answers:

5 0

The box plots show the data distributions for the number of customers who used a coupon each hour during a two-day sale. Which measure of variability can be

masya89 [10]3 years ago

3 0

Answer:

the table should show the data

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The formula below gives the area of a semi-circle, A, with a radius of r.

ch4aika [34]

Please provide the formula for me to answer

4 0

2 years ago

What is 2+2 then take away 1

laiz [17]

Answer:

Step-by-step explanation:

2 + 2 = 4

4 - 1 = 3

4 0

2 years ago

Read 2 more answers

I already found the vertex, but can someone help me find the latus rectum of this parabola?

Fofino [41]

Answer:

Step-by-step explanation:

y=x²+7

vertex(0,7)

the length of latus rectum in a parabola equal to four times the focal length :

y=x²+7

focus X=-b/2a=0

focus Y=c- (b²-1)/4a=7+1/4=29/4

focus (0 , 29/4)

latus rectum is 29/4

(x-h)^2 = 4p (y-k) 4p is the length of the latus rectum with vertex(0,7)

(0-0)²=4p(29/4-7)

0=29p-28p=1p

the length of the latus rectum is 1

8 0

2 years ago

Read 2 more answers

Given the function f(x) graphed on the coordinate plane 15

den301095 [7]

Answer:

Step-by-step explanation:

5 0

2 years ago

Analyzing a Graph In Exercise, analyze and sketch the graph of the function. Lable any relative extrema, points of inflection, a

Anit [1.1K]

Answer:

Analyzed and Sketched.

Step-by-step explanation:

We are given $y=\frac{\ln\left(5x)}{x^2}$

To sketch the graph we need to find 2 components.

1) First derivative of y with respect to x to determine the interval where function increases and decreases.

2) Second derivative of y with respect to x to determine the interval where function is concave up and concave down.

$y'=\frac{1-2\ln\left(5x)}{x^3}=0$

$x = \sqrt e/5$ is absolute maximum

$y''=\frac{6\ln\left(5x)-5}{x^4}=0$

$x=e^{5/6}/5$ is the point concavity changes from down to up.

Here, x = 0 is vertical asymptote and y = 0 is horizontal asymptote.

The graph is given in the attachment.

4 0

3 years ago