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gtnhenbr [62]
3 years ago
15

Conductors of large instrumental ensembles use thin stick called a __________ to help performers keep time.

Physics
2 answers:
Dmitry [639]3 years ago
6 0
I think the word is "baton"
kkurt [141]3 years ago
3 0
Your answer is:

baton

Hope this helps have a great day =D
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The stopwatch used by a student to measure velocity of a pulse in a slinky was of least count 0.1 second. He stops the stopwatch
sweet-ann [11.9K]

Least count of the pulse stopwatch is given by

\Delta t = 0.1 s

this means each division of the stopwatch will measure 0.1 s of time

After 3 journeys from one end to other we can see that total time that is measured here is shown by the clock as 52nd division

So here total time is given as

Time = (Number of division) (Least count)

now we will have

T = 52 \times 0.1s

T = 5.2 s

4 0
3 years ago
What are atoms and elements?
gizmo_the_mogwai [7]

Answer:

Atom, smallest unit into which matter can be divided without the release of electrically charged particles.

an element is a pure substance which cannot be broken down by chemical means

3 0
3 years ago
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The temperature and time t given in hours from 0 to 24 after midnight in downtown mathville is given by t=10-5 sin(pi/12 t) degr
Dvinal [7]

Answer:

T_A_v_g=9.918192559$^{\circ}C

Explanation:

The problem tell us that the temperature as function of time in downtown mathville is given by:

T(t)=10-5*sin(\frac{\pi}{12t})

The average temperature over a given interval can be calculated as:

T_a_v_g=\frac{T_o+T_f}{2}

Where:

T_o=Initial\hspace{3}temperature\\T_f=Final\hspace{3}temperature

So, the initial temperature in this case, would be the temperature at noon, and the final temperature would be the temperature at midnight:

Therefore:

T_o=T(12)=10-5*sin(\frac{\pi}{12*12}) =9.890925575$^{\circ}C

T_f=T(24)=10-5*sin(\frac{\pi}{12*24}) =9.945459543$^{\circ}C

Hence, the average temperature between noon and midnight is:

T_A_v_g=\frac{9.890925575+9.945459543}{2}=9.918192559$^{\circ}C

3 0
3 years ago
¿Qué distancia recorre un móvil que lleva una aceleración de 5m/s durante 10seg?
coldgirl [10]

Answer:

250 m

Explanation:

The car in this problem is moving of uniform accelerated motion, so we can use the following suvat equation:

s=ut+\frac{1}{2}at^2

where

s is the distance covered

u is the initial velocity

t is the time

a is the acceleration

Assuming the car starts from rest,

u = 0

Also we know that

a = 5 m/s^2 (acceleration of the car)

t = 10 s

Substituting, we find the distance covered:

s=0+\frac{1}{2}(5)(10)^2=250 m

3 0
3 years ago
Is the direction of current through a battery always from the negative terminal to the positive one?
rodikova [14]

Answer:

Yes. The current is actually flow of charge and in actual situation electrons flow from negative terminal to positive terminal. But in physics the convention of positive charge flow is used i.e. we take the direction of current from positive to negative terminal.

Explanation:

8 0
3 years ago
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