Solution:
a) We know acceleration due to gravity, g = GM/r²
Differential change, dg/dr = -2GM/r³
Here, r = 50*Rh = 50*2GM/c² = 100GM/c
²
My height, h=dr = 1.7 m
Difference in gravitational acceleration between my head and my feet, dg = -10 m/s²
or, dg/dr = -10/1.7 = -2GM/(100GM/c²)³
or, 5.9*100³*G²*M² = 2c⁶
or, M = 0.59*c³/(1000G) = 2.39*1032 kg = [(2.39*1032)/(1.99*1030 )]Ms = 120*Ms
Mass of black hole which we can tolerate at the given distance is 120 time the mass of Sun.
b) This limit an upper limit ,we can tolerate smaller masses only.
The question is not complete
Answer:
2.9 kg
Explanation:
Given that a 0.775-m3 rigid tank initially contains air whose density is 1.18 kg/m3.
According to the definition of density
Density = mass/volume
1.18 = mass / 0.775
Mass = 1.18 × 0.775
Mass = 0.9145 kg
Given that the tank is connected to a high-pressure supply line through a valve. The valve is opened, and air is allowed to enter the tank until the density in the tank rises to 4.95 kg/m3.
Using the same density formula
Density = mass/volume
4.95 = mass / 0.775
mass = 3.83625 kg
To determine the mass of air that has entered the tank, take away the mass of the air initial in the tank from the mass calculated
Mass = 3.83625 - 0.9145
Mass = 2.923kg
Therefore, the mass of air that has entered the tank is 2.9 kg approximately.
if it is heat flow through a metal, it would be necessary to have a conductor so that the electrons can flow through it (delocalised electrons).
In terms of radiation, it would require a good absorber of heat (e.g. a black surface) so that the thermal energy flows through on the surface area.
Answer:
Around the entire length of the wire
Explanation: