What is used to determine the number of each atom in an ionic formula?

A 1.0857 gram pure sample of a compound containing only carbon, hydrogen, and oxygen was burned in excess oxygen gas. 2.190 g of

Goryan [66]

Answer:

C₂ H₄ O

Explanation:

1) Mass of carbon (C) in 2.190 g of carbon dioxide (CO₂)

atomic mass of C: 12.0107 g/mol

molar mass of CO₂: 44.01 g/mol

Set a proportion: 12.0107 g of C / 44.01 g of CO₂ = x / 2.190 g of CO₂

Solve for x:

x = (12.0107 g of C / 44.01 g of CO₂ ) × 2.190 g of CO₂ = 0.59767 g of C

2) Mass of hydrogen (H) in 0.930 g of water (H₂O)

atomic mass of H: 1.00784 g/mol

molar mass of H₂O: 18.01528 g/mol

proportion: 2 × 1.00784 g of H / 18.01528 g of H₂O = x / 0.930 g of H₂O

Solve for x:

x = ( 2 × 1.00784 g of H / 18.01528 g of H₂O) × 0.930 g of H₂O = 0.10406 g of H

3) Mass of oxygen (O) in 1.0857 g of pure sample

Mass of O = mass of pure sample - mass of C - mass of H

Mass of O = 1.0857 g - 0.59767 g - 0.10406 = 0.38397 g O

Round to four decimals: Mass of O = 0.3840 g

4) Mole calculations

Divide the mass in grams of each element by its atomic mass:

C: 0.59767 g / 12.0107 g/mol = 0.04976 mol

H: 0.10406 g / 1.00784 g/mol = 0.10325 mol

O: 0.3840 g / 15.999 g/mol = 0.02400 mol

5) Divide every amount by the smallest value (to find the mole ratios)

C: 0.04976 mol / 0.02400 mol = 2.07 ≈ 2

H: 0.10325 mol / 0.02400 mol = 4.3 ≈ 4

O: 0.02400 mol / 0.02400 mol = 1

Thus the mole ratio is 2 : 4 : 1, and the empirical formula is:

C₂ H₄ O ← answer

3 0

3 years ago

Water is moving across a membrane from solution a into solution

leva [86]

The answer is solution a must have a lower solute concentration than solution b.

That is when water is moving across a membrane from solution a into solution b, then solution a must have a lower solute concentration than solution b.

When solution a have a lower solute concentration than solution b, then water moves across a membrane from solution a into solution b.

7 0

4 years ago

A balloon filled with 1.92 g of helium has a volume of 12.5 L. What is the balloon’s volume after 0.850 g of helium has leaked o

Marizza181 [45]

The answer is 1.56L. Avogadro's Law states that the volume of a gas is directly proportional to the number of moles (or a number of particles) of gas when the temperature and pressure are held constant.

V∝n

V₁/n₁m= V₂/n₂

V₁ = initial volume of gas = 12.5 L

V₂ = final volume of gas = ?

n₁ = initial moles of gas = 0.016 mole

n₂ = final moles of gas = 0.016-0.007 = 0.002 mole

V₁/n₁m= V₂/n₂

V₂= 1.56L

Avogadro's Law is in evidence whenever you blow up a balloon. The volume of the balloon increases as you add moles of gas to the balloon by blowing it up.

Learn more about Volume here:

brainly.com/question/5018408

#SPJ4

8 0

2 years ago

HELP HELP HELP ME PLSSSSS 50 POINTS

Anastaziya [24]

Answer:

1) They are the same line so they match equally bc they are measuring the same thing just one is more specific than the other

2) Sonar measures all depths at every possible point and maps it including all the gaps in between the 5cm apart the ocean floor is. The difference between the points could be a cliff or a smooth decline.

5 0

3 years ago

Read 2 more answers

A 3.140 molal solution of NaCl is prepared. How many grams of NaCl are present in a sample containing 2.692 kg of water

S_A_V [24]

Answer:

494.49 g of NaCl.

Explanation:

Data obtained from the question include the following:

Molality of NaCl = 3.140 m

Mass of water = 2.692 kg

Mass of NaCl =.?

Next, we shall determine the number of mole of NaCl in the solution.

Molality is simply defined as the mole of solute per unit kilogram of solvent. Mathematically, it is expressed as

Molality = mole of solute /Kg of solvent

With the above formula, we can obtain the number of mole NaCl in the solution as follow:

Molality of NaCl = 3.140 m

Mass of water = 2.692 kg

Mole of NaCl =..?

Molality = mole of solute /Kg of solvent

3.140 = mole of NaCl /2.692

Cross multiply

Mole of NaCl = 3.140 x 2.692

Mole of NaCl = 8.45288 moles

Finally, we shall covert 8.45288 moles of NaCl to grams. This can be obtained as follow:

Mole of NaCl = 8.45288 moles

Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol

Mass of NaCl =.?

Mole = mass /Molar mass

8.45288 = mass of NaCl /58.5

Cross multiply

Mass of NaCl = 8.45288 × 58.5

Mass of NaCl = 494.49 g.

Therefore, 494.49 g of NaCl are present in the solution.

8 0

3 years ago