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kotegsom [21]
3 years ago
8

Help please I need the answer

Chemistry
1 answer:
nexus9112 [7]3 years ago
5 0

Answer:

                    Polyatomic Ionic Compound

Explanation:

                     In given statement the compound given is called as Sodium oleate this means that when Oleic acid is treated with NaOH then it forms.

                     In chemistry there are few species which are involved in the formation of compounds.

  (i) Atoms:

                  It is very common that atoms of different elements combine to form compound through covalent bond. For example, H₂, O₂, N₂, F₂ e.t.c.

   (i) Ions:

                  Other than covalent compounds we have ionic compounds. Ionic compounds are made up of ions. These ions forming the ionic compounds can be monatomic like Na⁺, Br⁻, Mg²⁺, Al³⁺, N⁻³ or they can be polyatomic like CO₃²⁻, SO₄²⁻, NH₄⁺, PO₄³⁻ e.t.c.

    (iii) Polyatomic Ions:

                                     In polyatomic ions we find a charge on a molecule which contains two or more atoms bonded covalently. Hence, in given compound we have a long chain of molecule containing a negative charge neutralized by opposite +ve charged sodium ion. Hence, Sodium oleate is a polyatomic ionic compound.

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Cacl2+na3po4 ca3po42 + nacl
Alex787 [66]
<h3>Answer:</h3>

3CaCl₂ + 2Na₃PO₄→ Ca₃(PO₄)₂ + 6NaCl

<h3>Explanation:</h3>

We are given the Equation;

CaCl₂ + Na₃PO₄→ Ca₃(PO₄)₂ + NaCl

Assuming the question requires us to balance the equation;

  • A balanced chemical equation is one that has equal number of atoms of each element on both sides of the equation.
  • Balancing chemical equations ensures that they obey the law of conservation of mass in chemical equations.
  • According to the law of conservation of mass in chemical equation, the mass of the reactants should always be equal to the mass of the products.
  • Balancing chemical equations involves putting appropriate coefficients on the reactants and products.

In this case;

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3CaCl₂ + 2Na₃PO₄→ Ca₃(PO₄)₂ + 6NaCl

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3 years ago
You wish to construct a buffer of pH=7.0. Which of the following weak acids (w/ corresponding conjugate base) would you select?
Alex17521 [72]

Answer:

C.) HOCl Ka=3.5x10^-8

Explanation:

In order to a construct a buffer of pH= 7.0 we need to find the pKa values of all the acids given below

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B) similarly PKa of HF= -log(7.2 x 1 0^-4)= 2.7644

C)  pKa of HOCl= -log(3.5 x 1 0^-8)= 7.45

D) pKa of HCN = -log(4 x 1 0^-10)=  9.3979

If we consider the  Henderson- Hasselbalch equation for the calculation of the pH of the buffer solution

The weak acid for making the buffer must have a pKa value near to the desired pH of the weak acid.

So, near to value, pH=7.0. , the only option is HOCl whose pKa value is 7.45.

Hence, HOCl will be chosen for buffer construction.

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