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wariber [46]
3 years ago
11

How many moles of hydrochloric acid will react with one mole of aluminum hydroxide to produce a neutral solution

Chemistry
1 answer:
galina1969 [7]3 years ago
8 0

Answer: 3 moles of HCl

Explanation: let’s do a balanced chemical equation

Al(OH)3 + 3HCl —> AlCl3 + 3H2O

We see that for every 1 mole of Al(OH)3 we need 3 moles of HCl

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It takes much less energy to change the temperature of oil than it does to change the temperature of water
Andrew [12]

Answer:

i think so

Explanation:

8 0
3 years ago
The rate law of a reaction is rate = k[D][X]. The units of the rate constant are ________.
bogdanovich [222]

Answer:

D

Explanation:

Hello!

Since the rate must have the following units: mol/(L*s), the suitable units for k, considering that the term [D] [X] leads to mol^2/(L^2) (it means a second order kinetic law), are L/(mol*s), nevertheless, that answer isn't in the given options.

8 0
3 years ago
What is the mass of 2.65 millimoles of sulfur?
Bas_tet [7]
Divide this problem in to two steps: 1. Convert millimoles to moles. 2. Convert moles to grams.

1.
2.65 mlmol x 1mol/1000mlmol=.00265mol

2.
.00265mol x 32.065g/1 mol=.0850g S

Let me know if you need more explanation on why I used the conversions that I did.
6 0
3 years ago
pH indicator. A dye that is an acid and that appears as different colors in its protonated and deprotonated forms can be used as
Vitek1552 [10]

Answer:

pH = 7.8

Explanation:

The Henderson-Hasselbalch equation may be used to solve the problem:

pH = pKa + log([A⁻] / [HA])

The solution of concentration 0.001 M is a formal concentration, which means that it is the sum of the concentrations of the different forms of the acid. In order to find the concentration of the deprotonated form, the following equation is used:

[HA] + [A⁻] = 0.001 M

[A⁻] = 0.001 M - 0.0002 M = 0.0008 M

The values can then be substituted into the Henderson-Hasselbalch equation:

pH = 7.2 + log(0.0008M/0.0002M) = 7.8

7 0
3 years ago
The kb of hypochlorous acid is 3. 0×10^–8 at 26. 0 C. What is the percent of ionization of hypochlorous?
astraxan [27]

The acid dissociation constant (Ka) defines the difference between a weak and a strong acid. The % ionization of hypochlorous acid is 0.14%.

<h3>What is the acid dissociation constant?</h3>

The acid dissociation constant is used to define the ionization constant of an acidic substance. It gives the quantitative measurement of the strength.

The ICE table is attached to the image below.

The acid dissociation constant (Ka) for the reaction is,

Ka = [H⁺][ClO⁻] ÷ [HClO]

= a² ÷ (0.015 - a)

= 3.0 x 10⁻⁸

Now, a² + 3.0 x 10⁻⁸ a - 4.5 × 10⁻¹⁰ = 0

So, a = 2.210 × 10⁻⁵

Solving further,

[H+] = a = 2.210 × 10⁻⁵ M

The percent ionization is calculated as,

[H+] ÷ [HClO] × 100

= 2.210 × 10⁻⁵ M ÷ 0.015 × 100

= 0.14 %

Therefore, 0.14 % is the percentage of hypochlorous ionization.

Learn more about acid dissociation constant here:

brainly.com/question/22668939

#SPJ4

Your question is incomplete, but most probably your full question was, The ka of hypochlorous acid (HClO) is 3.0 x 10⁻⁸ at 25.0°C. What is the % of ionization of hypochlorous acid in a 0.015 aqueous solution of HClO at 25.0C?

6 0
1 year ago
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