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Nimfa-mama [501]
3 years ago
13

H3PO4 + Ca(OH)2 → Ca(H2PO4)2 + H2O

Chemistry
1 answer:
aniked [119]3 years ago
8 0

Given question is incomplete. The complete question is as follows.

Balance the following equation:

H_3PO_4 + Ca(OH)_2 \rightarrow Ca(H_2PO_4)_2 + H_2O

Answer: The balanced chemical equation is as follows.

2H_3PO_4 + Ca(OH)_2 \rightarrow Ca(H_2PO_4)_2 + 2H_2O

Explanation:

When a chemical equation contains same number of atoms on both reactant and product side then this equation is known as balanced equation.

For example, H_3PO_4 + Ca(OH)_2 \rightarrow Ca(H_2PO_4)_2 + H_2O

Number of atoms on reactant side:

H = 5

P = 1

O = 6

Ca = 1

Number of atoms on product side:

H = 6

P = 2

O = 9

Ca = 1

In order to balance this equation, we will multiply H_3PO_4 by 2 on reactant side and we will multiply H_2O by 2 on product side. Hence, the balanced chemical equation is as follows.

2H_3PO_4 + Ca(OH)_2 \rightarrow Ca(H_2PO_4)_2 + 2H_2O

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Answer: b. One atom transferring electrons to another atom

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Covalent bonds are formed by sharing of electrons between non metals

For example, In calcium iodide the one electron from calcium metal gets transferred to iodine atom and thus form an ionic bond to give CaI_2

Electronic configuration of calcium:

[Ca]=1s^22s^22p^63s^23p^64s^2

Calcium atom will lose two electron to gain noble gas configuration and form calcium cation with +2 charge.

[Ca^{2+}]=1s^22s^22p^63s^23p^6

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Iodine atom will gain one electron to gain noble gas configuration and form iodide ion with -1 charge.

[I^-]=1s^22s^22p^63s^23p^64s^23d^{10}4p^6

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The reaction which shows oxidation and reduction simultaneously is C₆H₁₂O₆(s) + 6O₂(g) → 6CO₂(g) + 6H₂O(l).

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Those reaction in which oxidation as well as reduction of substances takes place simultaneously will known as redox reactions.

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