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ipn [44]
3 years ago
11

Which is a benefit of strength training? O Decreased blood flow to muscles O Improved oxygen delivery Flexibility of tendons and

joints O Increased lean muscle tissue ​
Physics
1 answer:
Igoryamba3 years ago
8 0

Answer:

Increased lean muscle tissue.

Explanation:

I hope this helps :) Tell me if I am wrong!

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A 250 kg car has 6875 kg•m/s of momentum. What is it’s velocity?
liraira [26]

Answer:

v = 27.5 m/s

Explanation:

p = m × v

6,875 = 250 × v

250v = 6,875

v = 6,875/250

v = 27.5 m/s

5 0
3 years ago
What are the large, dark basaltic plains on the moon called?
faltersainse [42]
A.) LUNAR MARIA..............
7 0
4 years ago
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Three objects have velocities that vary with time
Solnce55 [7]

#21

  • initial velocity=u=5m/s
  • Time=t=2s
  • Acceleration=a=1.3m/s²

According to first equation of kinematics

  • v=u+at
  • v=5+1.3(2)
  • v=5+2.6
  • v=7.6m/s

#22

#a

  • v1=2+3(3)=2+9=11m/s
  • v2=-8-4(3)=-20m/s
  • v3=1-5(3)=-14m/s

The order is

  • v2<V3<v1

#b

for speed find absolute velocity

  • S1=|11|=11m/s
  • S2=|-20|=20m/s
  • S3=|-14|=14m/s

So order is

S1<S3<S2

7 0
2 years ago
Read 2 more answers
A 140 g baseball is moving horizontally to the right at 35 mis when it is hit by the bat. the ball fl ies off to the le ft at 55
Anit [1.1K]

Answer:

J = 12.32kg*m/s

Explanation:

Assumptions: I'm assuming mis is m/s

Given: The baseball's mass is 140g, so convert to kg, 0.140kg. (Good rule of thumb, in physics convert grams to kilograms). It is initially traveling 35 m/s to the right.

When it hits the bat, it flies left with a velocity of 55 m/s at an angle of 25°. To reiterate:

mass = 0.140kg, Initial: 35m/s, Final: 55m/s at an angle of 25°

For this problem, we have to use the impulse equation, but before that lets break the velocity into components (It will be apparent towards the end):

The initial velocity is moving only in the horizontal direction, so:

v_{0x} = 35 m/s

The final velocity has an x and a y component:

v_{fx} = 55cos(25) = 49.84692829m/s\\v_{fy} = 55sin(25) = 23.2440044m/s

Now the equation for impulse is (dp is Δp, which is difference in momentum; dv is Δv, the difference in velocity; J is impulse):

J = dp= m*dv

To get Δv, we have to find the difference of velocity, that is why we broke it into components. I'm going to define right as positive and left as negative. After that, we find the velocity vector:

dv_{x} = (35-(-49.84692829)) = 84.84692829 m/s\\dv_{y} = (0-(23.2440044)) = -23.2440044 m/s\\dv = \sqrt{(84.84692829)^2+(-23.2440044)^2} = 87.97320604m/s

Finally, substitute into the equation

J = m*dv\\J = 0.140kg * 87.97320604m/s\\J = 12.31624885kg*m/s\\J = 12.32 kg*m/s

J = 12.32kg*m/s

8 0
3 years ago
You are having a snowball fight with your best friend on a frosty winter day. You are standing on the roof of your 5 m tall hous
DENIUS [597]
In my own opinion I think it’s c
7 0
3 years ago
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