Answer:
a) ![F=1.044\times 10^9\ N](https://tex.z-dn.net/?f=F%3D1.044%5Ctimes%2010%5E9%5C%20N)
b)![F'=1.044\times 10^9\ N](https://tex.z-dn.net/?f=F%27%3D1.044%5Ctimes%2010%5E9%5C%20N)
c) ![F_p=1.0672\times10^{-7}\ N](https://tex.z-dn.net/?f=F_p%3D1.0672%5Ctimes10%5E%7B-7%7D%5C%20N)
d) Treat the humans as though they were points or uniform-density spheres.
Explanation:
Given:
- mass of Mars,
![M=6.4\times 10^{23}\ kg](https://tex.z-dn.net/?f=M%3D6.4%5Ctimes%2010%5E%7B23%7D%5C%20kg)
- radius of the Mars,
![r=3.4\times 10^{6}\ m](https://tex.z-dn.net/?f=r%3D3.4%5Ctimes%2010%5E%7B6%7D%5C%20m)
- mass of human,
![m=80\ kg](https://tex.z-dn.net/?f=m%3D80%5C%20kg)
a)
Gravitation force exerted by the Mars on the human body:
![F=G.\frac{M.m}{r^2}](https://tex.z-dn.net/?f=F%3DG.%5Cfrac%7BM.m%7D%7Br%5E2%7D)
where:
= gravitational constant
![F=6.67\times10^{-11}\times \frac{6.4\times 10^{23}\times 80}{(3.4\times 10^{6})^2}](https://tex.z-dn.net/?f=F%3D6.67%5Ctimes10%5E%7B-11%7D%5Ctimes%20%5Cfrac%7B6.4%5Ctimes%2010%5E%7B23%7D%5Ctimes%2080%7D%7B%283.4%5Ctimes%2010%5E%7B6%7D%29%5E2%7D)
![F=1.044\times 10^9\ N](https://tex.z-dn.net/?f=F%3D1.044%5Ctimes%2010%5E9%5C%20N)
b)
The magnitude of the gravitational force exerted by the human on Mars is equal to the force by the Mars on human.
![F'=F](https://tex.z-dn.net/?f=F%27%3DF)
![F'=1.044\times 10^9\ N](https://tex.z-dn.net/?f=F%27%3D1.044%5Ctimes%2010%5E9%5C%20N)
c)
When a similar person of the same mass is standing at a distance of 4 meters:
![F_p=6.67\times10^{-11}\times \frac{80\times 80}{4}](https://tex.z-dn.net/?f=F_p%3D6.67%5Ctimes10%5E%7B-11%7D%5Ctimes%20%5Cfrac%7B80%5Ctimes%2080%7D%7B4%7D)
![F_p=1.0672\times10^{-7}\ N](https://tex.z-dn.net/?f=F_p%3D1.0672%5Ctimes10%5E%7B-7%7D%5C%20N)
d)
The gravitational constant is a universal value and it remains constant in the Universe and does not depends on the size of the mass.
- Yes, we have to treat Mars as spherically symmetric so that its center of mass is at its geometric center.
- Yes, we also have to ignore the effect of sun, but as asked in the question we have to calculate the gravitational force only due to one body on another specific body which does not brings sun into picture of the consideration.
Answer:
The answer is 1.0 N
Explanation:
inclination of tray=12^{\circ}
gravitational Force=5 N
Now this gravitational force has two component i.e.
5\sin \theta is parallel to the tray =1.039 N
5\cos \theta is perpendicular to the tray =4.890 N
I am attaching the rest of your question so it makes sense,
<span>
Since lasers are made from stacking light waves that add together into a larger wave due to CONSTRUCTIVE INTERFERENCE.
</span>
Then, <span>light waves have that constructive interference (from question #1) because they are emitted IN PHASE with each other.
This means that they arrive at the same point of space with the same characteristics and their effects do not cancel each other, but the opposite, their intensity increases.</span>
<span>If Shelly rolls ball A in the positive x direction with a velocity of 7.5 meters/second, and It hits stationary ball B and they undergo elastic collision, thus the two balls have different masses, then the following statement which is true is the statement that stated that there was no y-momentum initially.</span>