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3 years ago

How is the combined gas law used to calculate changes in pressure, temperatures, and/or volume for a fixed amount of gas?

Physics

1 answer:

nalin [4]3 years ago

5 0

Answer:

Let's start by considering the ideal gas law:

$pV=nRT$

where

p is the gas pressure

V is its volume

n is the number of moles

R is the gas constant

T is the absolute temperature

This equation can also be rewritten as

$\frac{pV}{T}=nR$

Now, if we consider a fixed amount of gas, this means that the number of moles (n) is constant. So we can rewrite the equation as

$\frac{pV}{T}=const.$

And therefore, if we consider a gas undergoing a certain transformation from 1 to 2, we can write

$\frac{p_1V_1}{T_1}=\frac{p_2V_2}{T_2}$

where 1 indicates the conditions of the gas at the beginning and 2 the conditions of the gas after the process. So, the change in pressure/temperature/volume of the gas can be found by using this equation.

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Standing still at the top of the hill at point a,what kind of energy( potential and/or kinetic) would the snowboarder have ? How

Alja [10]

He would have potential, he hasn’t gone down the mountain yet so he remains potential

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3 years ago

What is the change in electric potential energy in moving an electron from a location 3 × 10-10 m from a proton to a location 7

joja [24]

Answer:

4.39 x 10^-19 J

Explanation:

q1 = 1.6 x 10^-19 C

q2 = - 1.6 x 10^-19 C

r1 = 3 x 10^-10 m

r2 = 7 x 10^-10 m

The formula for the potential energy is given by

U1 = k q1 q2 / r1 = - (9 x 10^9 x 1.6 x 10^-19 x 1.6 x 10^-19) / (3 x 10^-10)

U1 = - 7.68 x 10^-19 J

U2 = k q1 q2 / r2 = - (9 x 10^9 x 1.6 x 10^-19 x 1.6 x 10^-19) / (7 x 10^-10)

U2 = - 3.29 x 10^-19 J

Change in potential energy is

U2 - U1 = - 3.29 x 10^-19 + 7.68 x 10^-19 = 4.39 x 10^-19 J

5 0

4 years ago

Two identical positive charges exert a repulsive force of 6.2 × 10−9 n when separated by a distance 3.7 × 10−10 m. calculate the

In-s [12.5K]

The electrostatic force between two charges is given by
$F=k \frac{q_1 q_2}{r^2}$
where
k is the Coulomb's constant
q1 and q2 are the two charges
r is their separation

In this problem, the two charges are identical, so we can call them q1=q2=q, and the formula becomes
$F=k \frac{q^2}{r^2}$

Since we know the magnitude of the force and the separation between the two charges, we can re-arrange the equation to find the value of each charge:
$q= \sqrt{ \frac{Fr^2}{k} } = \sqrt{ \frac{(6.2 \cdot 10^{-9} N)(3.7 \cdot 10^{-10}m)^2}{8.99 \cdot 10^9 Nm^2C^{-2}} }=3.07 \cdot 10^{-19} C$

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3 years ago

Answer the question with step.

Maru [420]

Answer:

f1/f2 =W1/W2 = 1/3

.0 f2 = 3f1

As ,

1/F= 1/f1 +1/f2

...1/40 = 1/f1 - 1/3f1

f1=> 80/3 cm

... f2 = 2f1 = 3 x 80/3 = 80 cm

7 0

3 years ago

Alex swims at an average speed of 45 m/min. How far does he swim in 1 min 24 secs?

ohaa [14]

Answer:

SOLUTION: Alex swim at an average speed of 45 meters per seconds how far does he swim in 1 minutes and 24 seconds. 1 minute and 24 seconds is 84 seconds. If he swims 45 meters every second and he swims for 84 seconds, that means he swims: 45 * 84 = 3780 meters in 1 minute and 24 seconds.

Explanation:

You multiply 45 by 84 and that is equal to 3,780.

3 0

3 years ago