Answer: 211.059 m
Explanation:
We have the following data:
The angle at which the ball leaves the bat
The initial velocity of the ball
The acceleration due gravity
We need to find how far (horizontally) the ball travels in the air: 
Firstly we need to know this velocity has two components:
<u>Horizontally:</u>
(1)
(2)
<u>Vertically:</u>
(3)
(4)
On the other hand, when we talk about parabolic movement (as in this situation) the ball reaches its maximum height just in the middle of this parabola, when
and the time
is half the time it takes the complete parabolic path.
So, if we use the following equation, we will find
:
(5)
Isolating
:
(6)
(7)
(8)
Now that we have the time it takes to the ball to travel half of is path, we can find the total time
it takes the complete parabolic path, which is twice
:
(9)
With this result in mind, we can finally calculate how far the ball travels in the air:
(10)
Substituting (2) and (9) in (10):
(11)
Finally:
Answer:
Angular speed ω=3771.4 rad/min
Revolution=5921 rpm
Explanation:
Given data

To find
Angular speed ω
Revolution per minute N
Solution
First we need to convert the speed of truck to inches per mile
as
1 mile=63360 inches
1 hour=60 minutes
so

Now to solve for angular speed ω by substituting the speed v and radius r in below equation

To solve for N(revolutions per minute) by substituting the angular speed ω in the following equation
Electrical current will flow through a solid by the means of
electrons. The electrons in the solid
must be able to move from lower to higher electrical potential. The electric
current in certain solid electrolytes like ice is entirely composed of flowing
ions.
Answer:
TRUE
Explanation:
We currently live in the digital age, where almost everything is digitized, including strategic information. Thus, each individual and especially corporations that have sensitive data must use protection mechanisms against cyber attacks. One of the measures most recommended by experts is encryption, which consists of a set of rules that aims to encode data information so that only the sender and the receiver can decipher it.