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ExtremeBDS [4]
4 years ago
9

How do the reaction rates change as the system approaches equilibrium?

Chemistry
1 answer:
Leni [432]4 years ago
7 0
It becomes more stable
delta G gets closer to zero
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A compound composed of a metal and a nonmetal is dissolved in water the solution is been exposed to an electric current attached
solniwko [45]

Answer:

The answer to your question is:  Light bulb turns on

Explanation:

When we combine a metal and a nonmetal the product is a binary salt. Binary salts dissociate is solution and are good conductors of electricity.

Solutions of salt in water are called electrolytes.

In the question, they are describing a binary salt that is dissolve in water to produce an electrolyte, that means a good conductor of electricity.

5 0
3 years ago
Read the descriptions below of two substances and an experiment on each. Decide whether the result of the experiment tells you t
Phantasy [73]

Answer:

Samples A and B are mixtures

Explanation:

For sample A, we were told that the initial density of the solution is 0.77/gmL. After distillation, the liquid left has a density of 1.04/gmL. Apparently, A is a mixture of liquids.

As for sample B, the spread of the chromatogram resulting in different colours show that the sample B is not pure. It is a mixture of substances. A pure sample will yield only a single spot.

7 0
3 years ago
Is ivy a monocot or dicot
Aleksandr-060686 [28]

Answer:

dicot

Explanation:

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7 0
3 years ago
Which of the samples pictured is most likely a nonmetal?
max2010maxim [7]

Answer:

you need to be more specific

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Explanation:

7 0
3 years ago
A concentration cell is built based on the following half reactions by using two pieces of zinc as electrodes, two Zn2+ solution
Lana71 [14]

Explanation:

The given reaction at cathode will be as follows.

At cathode: Zn^{2+} + 2e^{-} \rightarrow Zn,     E_{o} = -0.761 V

At anode: Zn \rightarrow Zn^{2+} + 2e^{-},       E_{o} = 0.761

Therefore, net reaction equation will be as follows.

                 Zn^{2+} + Zn \rightarrow Zn + Zn^{2+}

Initial:     0.129         -            -       0.427

Change:  -0.047      -            -     -0.047

Equilibrium: (0.129 - 0.047)      (0.427 - 0.047)

                = 0.082                       = 0.38

As E^{o}_{cell} for the given reaction is zero.

Hence, equation for calculating new cell potential will be as follows.

                   E_{cell} = E^{o}_{cell} - \frac{RT}{nF} ln \frac{[Zn^{2+}]_{products}}{[Zn^{2+}]_{reactants}}

                              = 0 - \frac{8.314 atm L/mol K \times 291 K}{2 \times 96500} ln \frac{0.38}{0.082}

                              = 0.019

Thus, we can conclude that the cell potential of the given cell is 0.019.

3 0
4 years ago
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