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Anvisha [2.4K]
3 years ago
6

Differences in ocean water density are larger at low latitudes near the equator because the water temperature changes often thro

ughout the year
True or False
Chemistry
1 answer:
otez555 [7]3 years ago
4 0
Answer:

False i think

Explanation:

the water temp doesn’t fluctuate much near the equator.
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Brainless if correct
LuckyWell [14K]

Answer:

B

Explanation:

5 0
3 years ago
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Science 6th grade please help me :)
Gnom [1K]
I’m pretty sure the answer is D :)
6 0
3 years ago
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Instead of 6 M NaOH being added to the solution, 6 M HCl is added. How will this affect the test for the presence of ammonium io
Lera25 [3.4K]

Answer:

Ammonia gas(an alkaline gas with characteristics of choking or irritating smell) is not liberated when 6mole of HCl is added to the solution instead of 6mole of NaOH, to test for the presence of ammonium ion in the solution

Explanation:

As expected, when testing for ammonium ion in a solution (precisely ammonium salt solution), Sodium Hydroxide (NaOH) is required as the test reagent.

When NaOH is added to the solution, A gas with characteristics of choking or irritating smell is liberated.

This gas turn red litmus paper blue.

This liberated gas is an alkaline gas, which is confirmed as an ammonia gas(NH3).

If HCl is added instead of NaOH, the ammonia gas will not be liberated, which indicates that the test reagent used is wrong.

3 0
3 years ago
Based on what you’ve determined regarding one mole of sand and one mole of water, which statements must be correct? Select all t
Igoryamba

Answer:

-The mole is appropriate only for counting things that are very small.

-One mole is a very large number of something.

-A molecule of water is much smaller than a grain of sand.

Explanation:

8 0
3 years ago
Please help me with this question!!
mestny [16]

Answer: 824.6 g of NaCl are produced from 500.0 g of chlorine.

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}  \text{Moles of} Cl_2=\frac{500.00g}{71g/mol}=7.04moles

2Na+Cl_2\rightarrow 2NaCl  

According to stoichiometry :

1 mole of Cl_2 produce = 2 moles of NaCl

Thus 7.04 moles of Cl_2 will produce=\frac{2}{1}\times 7.04=14.08moles  of NaCl

Mass of NaCl=moles\times {\text {Molar mass}}=14.08moles\times 58.5g/mol=824.26g

Thus 824.6 g of NaCl are produced from 500.0 g of chlorine.

3 0
3 years ago
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