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Anvisha [2.4K]
3 years ago
6

Differences in ocean water density are larger at low latitudes near the equator because the water temperature changes often thro

ughout the year
True or False
Chemistry
1 answer:
otez555 [7]3 years ago
4 0
Answer:

False i think

Explanation:

the water temp doesn’t fluctuate much near the equator.
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commercial cold packs consist of solid NH4NO3 and water. In a coffee-cup calorimeter, 5.60g NH4NO3 is dissolved in 100g of water
fgiga [73]

Answer:

-1.37 kJ/mol

Explanation:

The expression for the calculation of the enthalpy of dissolution of [tex[NH_4NO_3[/tex] is shown below as:-

\Delta H=m\times C\times \Delta T

Where,  

\Delta H  is the enthalpy of dissolution of [tex[NH_4NO_3[/tex]

m is the mass

C is the specific heat capacity

\Delta T  is the temperature change

Thus, given that:-

Mass of ammonium nitrate = 5.60 g

Specific heat = 4.18 J/g°C

\Delta T=17.9-22.0\ ^0C=-4.1\ ^0C

So,  

\Delta H=-1.25\times 4.18\times 3.9\ J=-95.9728\ J

Negative sign signifies loss of heat.  

Also, 1 J = 0.001 kJ

So,  

\Delta H=-0.096\ kJ

Also,

Molar mass of [tex[NH_4NO_3[/tex] = 80.043 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{5.60\ g}{80.043 \ g/mol}

Moles= 0.06996\ mol

Thus, \Delta H=-\frac{0.096}{0.06996}\ kJ/mol=-1.37\ kJ/mol

6 0
4 years ago
A cup of coffee (140g) cools from 75°C down to comfortable room temperature 20°C. How much energy does it release to the surroun
Thepotemich [5.8K]

Given that the mass of coffee in the cup = 140 g

Final temperature = 20^{0}C

Initial temperature = 75^{0}C

Let us assume the specific heat of coffee is equal to that of water = 4.184\frac{J}{g^{0}C }

Temperature change = T(final) - T(initial) = (20 - 75 )^{0}C

                                                                   =- 55 ^{0}C

-Heat given out by coffee = heat absorbed by the surroundings

Heat released into the surroundings =-(mC(T_{final}-T_{initial}))

                                             = -(140g)4.184\frac{J}{g^{0}C }( -55^{0}C)

                                             = 32,217 J

4 0
4 years ago
The law of universal gravitation was discovered by .
anzhelika [568]
The person who discovered universal gravitation was newton.
7 0
3 years ago
Read 2 more answers
Please help me immediately I will mark you as brainiest.
IrinaVladis [17]
There's 18 atoms in ammonium phosphate
5 0
3 years ago
The following list contains some common polyatomic ions. Using the charge on these ions and the idea of valence, predict the for
SSSSS [86.1K]

Answer: Na_2CO_3 or Sodium carbonate.

              KMnO_4 or Potassium permanganate

Sodium ion carries 1 + charge whereas carbonate ion carries overall charge of -2. So for every carbonate ion, two sodium ions combine to balance the charges and thus form a stable compound, Na_2CO_3

Potassium ion carries 1 + charge where as permanganate ion carries overall charge of -1. So for every permanganate ion, one potassium ion combines to balance the charges and thus form a stable compound,  KMnO_4

The predicted formulas are shown in the attached image.


5 0
3 years ago
Read 2 more answers
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