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Brut [27]
3 years ago
14

What are the unit for acceleration

Physics
1 answer:
il63 [147K]3 years ago
3 0

the SL unit of acceleration is the meter per second squared

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If the caffeine concentration in a particular brand of soda is 2.97 mg/oz, 2.97 mg/oz, drinking how many cans of soda would be l
Ray Of Light [21]

Explanation:

The given data is as follows.

     Concentration of caffeine = 2.97 mg/oz

     Number of oz in a can = 12 oz

Therefore, the concentration of caffeine in one can is calculated as follows.

                 = (12 \times 2.97) mg

                 = 35.64 mg

                 = 35.64 \times 10^{-3} g

Since, it is given that lethal dose is 10.0 g. Hence, number of cans are calculated as follows.

     No. of cans = \frac{\text{Lethal dose}}{\text{concentration in one can}}

                         = \frac{10 g}{35.64 \times 10^{-3} g}

                         = 280.58

                         = 281 (approx)

Thus, we can conclude that 281 cans of soda would be lethal.

5 0
3 years ago
What type of energy do you observe from a light bulb
Lunna [17]
Potential if it is off or kinetic energy when its on
3 0
3 years ago
The Robinson projection map is considered very useful because
Vladimir79 [104]
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7 0
3 years ago
a square loop of wire side 3.0 cm carries 3.0 A of current. A uniform magnetic field of magnitude 0.67 T makes an angle of 37 de
Varvara68 [4.7K]

Explanation:

Below is an attachment containing the solution.

8 0
3 years ago
The 9 kg block is then released and accelerates to the right, toward the 5 kg block. The surface is rough and the coefficient of
Ahat [919]

Complete Question

The complete question is shown on the first and second uploaded image

Answer:

The velocity is  =4.51m/s  

Explanation:

The kinetic energy of the 9 kg can be determined by these expression

        Kinetic energy of 9 kg  block = initial energy stored - energy lost as a result of friction

  Now to obtain the initial energy stored

               Let U denote the initial energy stored and

                      U  = \frac{1}{2} kx^2

Where x  is the length the spring is displaced

k is the force constant of the string

         U = \frac{1}{2} * 627 * (0.6)^2

          = 112.86 J

   Now referring to the formula above

i.e          Kinetic energy of 9 kg  block = initial energy stored - energy lost as a result of friction

                \frac{1}{2} mv^2 = 112.86 - \mu_kmgx

                v^2 = \frac{2(112.86 -\mu_kmgx)}{m}

                v = \sqrt{\frac{2(112,86- \mu_kmgx)}{m}}

and we are told that coefficient of friction  = 0.4 and the mass is 9 kg ,the acceleration due to gravity = 9.8m/s^2  this displacement length of spring = 0.6

  Therefore   v = \sqrt{\frac{2(112.86- (0.4 *9*9.8*0.6))}{9} }

                        =4.51m/s      

           

8 0
3 years ago
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