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2 years ago

Sulfur powder (S) and oxygen gas (O2) undergo a

Chemistry

2 answers:

Zigmanuir [339]2 years ago

5 0

S (s) + O₂ (g) → SO₂ (aq) represents this chemical reaction

<h3>Further explanation</h3>

In stating a chemical equation it can be done in the form of a word or a chemical formula

A word equation will include the words of the reactants, products, form of the compound (liquid, gas, solid), the total concentration/quantity of the reactants and products which can be expressed in mass, moles, or volume

The questions statement above shows that sulfur powder (S) and oxygen gas (O₂) are reactants (located on the left of the reaction equation), and sulfur dioxide (SO₂) is the product of the reaction (stated in the problem there is the word "to form") which is located on the right

So the complete reaction

S (s) + O₂ (g) → SO₂ (aq)

MaRussiya [10]2 years ago

4 0

Answer:

The correct answer is A

Explanation:

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CH4 + 202 → CO2 + 2H2O<br> How many grams of O2 needed to produce 36 grams of H2O?

Kipish [7]

<h3>Answer:</h3>

64 g O₂

<h3>General Formulas and Concepts:</h3>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced] CH₄ + 2O₂ → CO₂ + 2H₂O

[Given] 36 g H₂O

[Solve] x g O₂

<u>Step 2: Identify Conversions</u>

[RxN] 2 mol O₂ → 2 mol H₂O

[PT] Molar Mass of O - 16.00 g/mol

[PT] Molar Mas of H - 1.01 g/mol

Molar Mass of O₂ - 2(16.00) = 32.00 g/mol

Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol

<u>Step 3: Stoichiometry</u>

Set up conversion: $\displaystyle 36 \ g \ H_2O(\frac{1 \ mol \ H_2O}{18.02 \ g \ H_2O})(\frac{2 \ mol \ O_2}{2 \ mol \ H_2O})(\frac{32.00 \ g \ O_2}{1 \ mol \ O_2})$
Divide/Multiply [Cancel Units]: $\displaystyle 63.929 \ g \ O_2$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

63.929 g O₂ ≈ 64 g O₂

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CH3 is a methyl radical, which is formed by removing the hydrogen atom from methane, so the hybridization is SP^3

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Sue dissolved a certain amount of salt in 400 grams of water to obtain 405 grams of salt solution. What was the mass of the salt

svp [43]

The answer would be 5 grams of salt

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Examine the following equations.

Alex

Answer: (A) and (D)

Options (A) and (D) represent beta decay.

Explanation:

It is very simple to find beta decay in a nuclear reaction. In beta decay , neutron breaks down into a proton and an electron. After that electron is emitted from the nucleus,while proton remains inside nucleus. The resulting daughter nuclei will have one more proton and one less neutron.

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Anabolic reactions _______ bonds, whereas catabolic reactions __________ bonds. A. decrease; increase. B. break; make C. weaken;

nexus9112 [7]

Answer:

The corrext answer is E. make; break

Explanation:

In living organisms, the metabolism is either anabolic or catabolic where anabolic metabolism is energy consuming and catabolic metabolism is eneegy releasesing. It should however be noted that anabolic reaction builds or biosynthesize new mollecular structures while catabolic reaction breaks down complex structure bonds into simple structures

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