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Ilia_Sergeevich [38]
3 years ago
6

In which direction does the electric field point at a position directly north of a positive charge?

Physics
2 answers:
UNO [17]3 years ago
7 0

Answer:

South

Explanation:

navik [9.2K]3 years ago
5 0

Answer:

B. South

Explanation:

An electric field can be defined as the amount of electric force per unit charge. The direction of the electric field can be determined by the motion of a positive test charge under the electric force.

The direction of electric field is radially outward for a positive charge and radially inward for a negative charge. Thus, for the electric field points toward SOUTH at a position directly south of a positive charge.

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A string exerts a force of 20 N on a box at an angle of 38° from the horizontal. What is the horizontal
Gnoma [55]

Answer:

15.76N

Explanation:

horizontal component =Fcos¢ = 20cos38 = 15.76N

4 0
2 years ago
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Calculate the frequency of visible light having a wavelength of 410 nm
maria [59]
Given: Wavelength λ = 410 nm  convert to Meters m = 4.10 x 10⁻⁷ m

Speed of light c = 3 x 10⁸ m/s

Required: Frequency  f = ?

Formula: c = λf 

               f = c/λ

               f = 3 x 10⁸ m/s/4.10 x 10⁻⁷ m

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6 0
3 years ago
The Steamboat Geyser in Yellowstone National Park shoots water into the air at 48.0 m/s. How
qwelly [4]

Answer:

The maximum height reached by the water is 117.55 m.

Explanation:

Given;

initial velocity of the water, u = 48 m/s

at maximum height the final velocity will be zero, v = 0

the water is going upwards, i.e in the negative direction of gravity, g = -9.8 m/s².

The maximum height reached by the water is calculated as follows;

v² = u² + 2gh

where;

h is the maximum height reached by the water

0 = u² + 2gh

0 = (48)² + ( 2 x -9.8 x h)

0 = 2304 - 19.6h

19.6h = 2304

h = 2304 / 19.6

h = 117.55 m

Therefore, the maximum height reached by the water is 117.55 m.

7 0
2 years ago
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Which of the following biomes might be found at a latitude of 33° South?
cupoosta [38]
The answer is going be desert. 
5 0
3 years ago
A proton is accelerated from rest through a potential difference of 2.5 kV and then moves perpendicularly through a uniform 0.60
Bumek [7]

Answer:

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V=(2ev/m)^1/2

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=0.012m

=1.2cm

5 0
3 years ago
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