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Anika [276]
2 years ago
6

If point (2, 3) is rotated 270 degrees, what will be the new coordinate point?

Mathematics
1 answer:
Yanka [14]2 years ago
3 0

Answer:

-2,-3

Step-by-step explanation:

multiply the x coordinate and the y coordinate by -1 and interchange the x and y-coordinates

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***WILL GIVE BRAINLIEST***
AlekseyPX

Answer:

a.) Selecting two red balls (because there are more red balls than white)

OR

c.) Selecting 1 red ball and then 1 white ball (because there is also a chance of selecting a white ball after selecting a red ball)

(Not kinda sure)

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4 0
2 years ago
Please double check for me :)<br><br> Did I select the correct boxes?
geniusboy [140]

Hi there, Queen Tima! I hope you're having a great day today!!

You selected the correct boxes!

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5 0
3 years ago
Read 2 more answers
Suppose a family has four children. What is the probability that at least two are female?
tamaranim1 [39]
P(all 4 are male) = 1/2^4 = 1/16  ( assuming  probability of 1 male = 1/2)

P( 3 are male) =   1/2^4*4  = 1/4

The rest will have at least 2 females

So probability of at least 2 females) = 1 - 1/16 - 1/4 =  1 - 5/16 = 11/16 answer
4 0
3 years ago
In a sample of 100 randomly selected concert attendees, the concert organizers find that 11 of them left the show early. The con
3241004551 [841]

Answer:

A) ≈22.4 concert attendees might have left early.

B) 605 attendees might leave early.

Step-by-step explanation:

A) 11/100, or 11%, of the sample left early.

    11% of all the concert attendees is (11/100) × 2040 ≅ 22.4

    attendees who might have left early.

B) 11% of the total attendance is 11% × 5500 = 605 attendees who might

    leave early.

8 0
3 years ago
Question 7 of 10
andriy [413]

Answer:

C. n = 90; p = 0.8

Step-by-step explanation:

According to the Central Limit Theorem, the distribution of the sample means will be approximately normally distributed when the sample size, 'n', is equal to or larger than 30, and the shape of sample distribution of sample proportions with a population proportion, 'p' is normal IF n·p ≥ 10 and n·(1 - p) ≥ 10

Analyzing  the given options, we have;

A. n = 45, p = 0.8

∴ n·p = 45 × 0.8 = 36 > 10

n·(1 - p) = 45 × (1 - 0.8) = 9 < 10

Given that for n = 45, p = 0.8, n·(1 - p) = 9 < 10, a normal distribution can not be used to approximate the sampling distribution

B. n = 90, p = 0.9

∴ n·p = 90 × 0.9 = 81 > 10

n·(1 - p) = 90 × (1 - 0.9) = 9 < 10

Given that for n = 90, p = 0.9, n·(1 - p) = 9  < 10, a normal distribution can not be used to approximate the sampling distribution

C. n = 90, p = 0.8

∴ n·p = 90 × 0.8 = 72 > 10

n·(1 - p) = 90 × (1 - 0.8) = 18 > 10

Given that for n = 90, p = 0.9, n·(1 - p) = 18 > 10, a normal distribution can be used to approximate the sampling distribution

D. n = 45, p = 0.9

∴ n·p = 45 × 0.9 = 40.5 > 10

n·(1 - p) = 45 × (1 - 0.9) = 4.5 < 10

Given that for n = 45, p = 0.9, n·(1 - p) = 4.5 < 10, a normal distribution can not be used to approximate the sampling distribution

A sampling distribution Normal Curve

45 × (1 - 0.8) = 9

90 × (1 - 0.9) = 9

90 × (1 - 0.8) = 18

45 × (1 - 0.9) = 4.5

Now we will investigate the shape of the sampling distribution of sample means. When we were discussing the sampling distribution of sample proportions, we said that this distribution is approximately normal if np ≥ 10 and n(1 – p) ≥ 10. In other words

Therefore;

A normal curve can be used to approximate the sampling distribution of only option C. n = 90; p = 0.8

3 0
2 years ago
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