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3 years ago

Which of the following chemical formulas could represent a stable compound formed with an element "X" from group 1A and Oxygen?

Chemistry

1 answer:

vaieri [72.5K]3 years ago

6 0

Answer:

2. X₂O

Explanation:

Elements in group 1A are known as alkali metal. Examples include lithium, sodium, and potassium among others.
These elements have one valence electron in the outermost energy level and therefore form cations with a charge of +1.
They have a valency of 2.
Oxygen, on the other hand,has a valency of 2.
Therefore, a chemical formula of a compound formed when an element in group 1A say X reacts with oxygen will be X₂O.
To write the formula, we identify the symbol of the elements and their valence.
Then the atoms of the two elements exchange their valencies which are written as a subscript on each symbol of an element.

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If 45.0 mL of ethanol (density=0.789 g/mL) initially at 9.0 C is mixed with 45.0 mL of water (density=1.0 g/mL) initially at 28.

Klio2033 [76]

Answer : The final temperature of the mixture is $22.7^oC$

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

$q_1=-q_2$

$m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)$

And as we know that,

Mass = Density × Volume

Thus, the formula becomes,

$(\rho_1\times V_1)\times c_1\times (T_f-T_1)=-(\rho_2\times V_2)\times c_2\times (T_f-T_2)$

where,

$c_1$ = specific heat of ethanol = $2.3J/g^oC$

$c_2$ = specific heat of water = $4.18J/g^oC$

$m_1$ = mass of ethanol

$m_2$ = mass of water

$\rho_1$ = density of ethanol = 0.789 g/mL

$\rho_2$ = density of water = 1.0 g/mL

$V_1$ = volume of ethanol = 45.0 mL

$V_2$ = volume of water = 45.0 mL

$T_f$ = final temperature of mixture = ?

$T_1$ = initial temperature of ethanol = $9.0^oC$

$T_2$ = initial temperature of water = $28.6^oC$

Now put all the given values in the above formula, we get

$(0.789g/mL\times 45.0mL)\times (2.3J/g^oC)\times (T_f-9.0)^oC=-(1.0g/mL\times 45.0mL)\times 4.18J/g^oC\times (T_f-28.6)^oC$

$T_f=22.7^oC$

Therefore, the final temperature of the mixture is $22.7^oC$

4 0

3 years ago

Boyle's Law represents the relationship of volume as pressure changes. The constants of Boyle's Law are:

Aleksandr [31]

Answer:

d. Temperature and number of molecules of gas

Step-by-step explanation:

Boyle's Law states, "The volume of a fixed mass of a gas is inversely proportional to the pressure if the temperature remains constant."

Let's examine the words.

"… volume…is inversely proportional to the pressure …" This means that volume and pressure are the variables.

"… fixed mass of a gas …" means that the number of molecules is constant.

"… temperature remains constant" speaks for itself.

a, c, and e are wrong, because pressure is a variable.

b is wrong, because volume is a variable.

5 0

3 years ago

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Answer:

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vovikov84 [41]

Answer:

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Explanation:

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3 years ago