Answer:
Explanation:
According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.
The balanced chemical equation for reaction of potassium superoxide with carbon dioxide to produce oxygen and potassium carbonate will be:
Answer:
Value of equilibrium constant is 0.0888
Explanation:
Both and
are gaseous. Hence equilibrium constant depends upon partial pressures of
and
.
Initially no and
were present.
Hence mole fraction of and
at equilibrium can be calculated from coefficient of
and
in balanced equation.
Mole fraction of = (number of moles of
)/(total number of moles of
and
) =
Mole fraction of = (number of moles of
)/(total number of moles of
and
) =
Let's assume both and
behaves ideally.
Therefore partial pressure of ,
and P_{CO_{2}}= x_{CO_{2}}.P_{total}
Where x represents mole fraction
So,
So,
Answer:
The options e and d are correct.
Explanation:
Mass of NiO = 7.5 g
Moles of NiO =
Moles of sulfuric acid = n
Volume of sulfuric acid ,V= 50 mL = 0.050 L
Molarity of sulfuric acid ,M = 6 mol/L
According to reaction, 1 mole of NiO reacts with 1 mole of sulfuric acid.
Then 0.10 moles of NiO reacts with :
of sulfuric acid.
As we can see that sulfuric acid is in excess amount, so the amount of the product will depend upon amount of NiO.
According to reaction, 1 mole of NiO gives with 1 mole of .
Then 0.10 moles of NiO wil give :
of
.
Molar mass of = 154.75 g/mol
Mass of 0.10 moles of :
= 154.75 g/mol × 0.10 mol = 15.475 g
Theoretical mass of = 15.475 g
Experimental yield of = 17.4 g
Percentage yield :
Percentage yield of :
Moles of = 262.85 g/mol × 0.10 mol = 26.285 g
Experimental yield of = 17.4 g
Percentage yield of :