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alexandr402 [8]
3 years ago
9

What has 9 protons and -1 charge? PLEASE HELP ME

Chemistry
1 answer:
Ksenya-84 [330]3 years ago
4 0

Fluorine, I still remember this from my science fair

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Be sure to answer all parts. Nitric oxide, NO·, is a radical thought to cause ozone destruction by a mechanism similar to that o
SIZIF [17.4K]

Answer:

See image attached and explanation

Explanation:

The stratospheric ozone layer is very important in absorbing high-energy ultraviolet radiation that is harmful to living systems on earth. The concentration of ozone in the stratosphere is determined by both thermal and photochemical pathways for its decomposition. Nitric oxide, NO, is a trace constituent in the stratosphere that reacts with ozone to form nitrogen dioxide, NO2, and the diatomic oxygen molecule. The nitrogen-oxygen bond in NO2 is relatively weak. When an NO2 molecule encounters an oxygen atom, it transfers an oxygen, forming O2 and NO. The chemical reactions involved are formations of NO2 following by reaction of NO2 with atomic oxygen for form NO and O2. The sum of both reactions show that the overall reaction is simply the reaction of ozone with atomic oxygen to form two molecules of molecular oxygen. Hence, NO only serves as a catalyst, it does not undergo a permanent change itself.

6 0
3 years ago
question #5: corals are sensitive to temperature . if temperatures are raised , it will cause the coral to bleach . what does bl
larisa86 [58]

Answer:

coral bleaching is when the temperature of the water changes (even slight changes in temperature effect coral) and the coral reacts negatively to it causing it to die. unfortunately corals cannot recover once they have been bleached.  

3 0
3 years ago
Read 2 more answers
Whats the difference between an atom and an ion?
Tpy6a [65]

An atom is the fundamental unit of matter and it contains an equal number of protons and electrons in its nucleus which makes it electrically neutral. An ion however, is an atom containing an unequal number of protons and electrons which means it will either carry a net positive charge or negative charge depending on whether there are more electrons or protons.

7 0
3 years ago
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What is the standard potential, e∘celle∘cell, for this galvanic cell? use the given standard reduction potentials in your calcul
Olin [163]

The standard potential for the given galvanic cell is 0.477 V

<h3>What is electrode potential?</h3>

The electrode potential is the electromotive force of a galvanic cell built using a standard reference electrode and another electrode whose potential is to be found.

There are two types of electrode potential

Oxidation potential - The potential associated with oxidation reaction is known as oxidation potential

Reduction potential - The potential associated with reduction reaction is known as reduction potential

At the anode, oxidation occurs

Sn(s)\rightarrow Sn^{2+}(aq)+2e^-

At the cathode, reduction occurs

Cu^{2+}(aq)+2e^-\rightarrow Cu(s)

E^o_{cell} =E^o_{cathode} -E^o_{anode}

        = 0.337 - (-0.140)

        = 0.477 V

Thus, The standard potential for the given galvanic cell is 0.477 V

Learn more about electrode potential:

brainly.com/question/17362810

#SPJ4

Disclaimer: The question was given incomplete on the portal. Here is the complete question

Question: What is the standard potential, E∘cell, for this galvanic cell? Use the given standard reduction potentials in your calculation as appropriate.

Sn^{2+}(aq)+2e^-\rightarrow Sn(s), E°red=−0.140 V

Cu^{2+}(aq)+2e^-\rightarrow Cu(s), E°red=+0.337 V

4 0
2 years ago
Read 2 more answers
Oxidation of gaseous ClF by F2 yields liquid ClF3, an important fluorinating agent. Use the following thermochemical equations t
natka813 [3]

Answer:

ΔH = -135.05 kJ

Explanation:

(1) 2 ClF(g) + O₂(g) → Cl₂O(g) + OF₂(g)           ΔHo = 167.5 kJ

(2) 2 F₂(g) + O₂(g) → 2 OF₂(g)                         ΔHo = −43.5 kJ

(3) 2 ClF₃(l) + 2 O₂(g) → Cl₂O(g) + 3 OF₂(g)    ΔHo = 394.1 kJ

We can use Hess' Law to calculate the  ΔH of reaction:

ClF(g) + 1/2O₂(g) → 1/2Cl₂O(g) + 1/2OF₂(g)  ΔHo = 167.5  x 1/2 = 83.75 kJ

F₂(g) + 1/2O₂(g) →  OF₂(g)                             ΔHo = −43.5   x 1/2 = -21.75 kJ

1/2Cl₂O(g) + 3/2 OF₂(g) →  ClF₃(l) +  O₂(g)   ΔHo = 394.1  x -1 x 1/2 = -197.05kJ

______________________________________________

(4) ClF (g) + F₂ (g) → ClF₃ (l)      ΔH = 83.75 kJ-21.75 kJ-197.05kJ

ΔH = -135.05 kJ/mol

5 0
4 years ago
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