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kicyunya [14]
3 years ago
14

Question 39 (1 point)

Chemistry
1 answer:
NemiM [27]3 years ago
5 0

Answer:

volume = 2128L

Explanation:

volume at stp = 22.4dm³ =22400L

CO2 = 12 + 2(16) = 44

4.20/44 = volume/22400L

0.095 = volume/22400L

volume = 0.095 x 22400

volume = 2128L

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Examine the given reaction. NH4NO3(s) → NH4+(aq) + NO3–(aq) ΔH° = 25.45 kJ/mol ΔS° = 108.7 J/mol·K Which of the given is correct
kobusy [5.1K]

Answer:

B)−6,942 J /mol

Explanation:

At constant temperature and pressure, you cand define the change in Gibbs free energy, ΔG, as:

ΔG = ΔH - TΔS

Where ΔH is enthalpy, T absolute temperature and ΔS change in entropy.

Replacing (25°C = 273 + 25 = 298K; 25.45kJ/mol = 25450J/mol):

ΔG = ΔH - TΔS

ΔG = 25450J/mol - 298K×108.7J/molK

ΔG = -6942.6J/mol

Right solution is:

<h3>B)−6,942 J /mol</h3>

8 0
3 years ago
What is the nuclear binding energy of an atom that has a mass defect of 5.0446 x 10-29 kg?
lutik1710 [3]
I think it is 4.54 x 10-12
3 0
2 years ago
Read 2 more answers
Which of the following atoms would have the greatest velocity of each atom had the same kinetic energy?
storchak [24]
The answer would be C oxygen
3 0
3 years ago
Read 2 more answers
How does a chemist count the number of particles in a given number of moles of a substance?
jolli1 [7]
The chemist the count the number of particles (Atoms, Molecules or Formula Unit) in a given number of moles of a substance by using following relationship.

                              Moles  =  # of Particles / 6.022 × 10²³

Or,

                              # of Particles  =  Moles × 6.022 × 10²³

So, from above relation it is found that 1 mole of any substance contains exactly 6.022 × 10²³ particles. Greater the number of moles greater will be the number of particles.
8 0
3 years ago
How much heat must your body transfer to 500.0g of water to heat it from 25.0°C to body temperature, 37.0°C?
shtirl [24]

Answer : The heat your body transfer must be, 25.1 kJ

Explanation :

Formula used :

Q=m\times c\times \Delta T

or,

Q=m\times c\times (T_2-T_1)

where,

Q = heat = ?

m = mass of water = 500.0 g

c = specific heat of water = 4.18J/g^oC

T_1 = initial temperature  = 25.0^oC

T_2 = final temperature  = 37.0^oC

Now put all the given value in the above formula, we get:

Q=500.0g\times 4.18J/g^oC\times (37.0-25.0)K

Q=25080J=25.1kJ

Therefore, the heat your body transfer must be, 25.1 kJ

3 0
2 years ago
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