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lora16 [44]
2 years ago
14

What two factors affect the force of friction?

Chemistry
2 answers:
Vlad1618 [11]2 years ago
6 0

Answer : Option C) Roughness of the surface and weight of the object.

Explanation : The factors that affect the forces of friction are roughness of the surface and weight of the object.

Friction is the force which resists the relative motion of solid surfaces, fluid layers, and material elements which are sliding against each other.

Friction depends on the normal force and the roughness of the surface which is in contact. When a body is placed on the ground, the mass of the body which is weight = mass x acceleration due to gravity, comes into play for the normal force from the ground. This clearly shows that friction is affected by weight as it depends on the mass of the object.

It also depends partly on the smoothness of the contacting surfaces, if a greater force being applied to move two surfaces past one another then they are rough, if they were smooth less force would have been applied for moving it.

Sav [38]2 years ago
3 0
Roughness of the surface and weight of the object.
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A alkaline earth metal is an element is groups 3-12 of the periodic table true or false?
Karo-lina-s [1.5K]

False Alkaline earth metals is group 2

5 0
2 years ago
A gas mixture with a total pressure of 745 mmHg contains each of the following gases at the indicated partial pressures: CO2, 24
Setler79 [48]

<u>Answer:</u>

<u>For Part A:</u> The partial pressure of Helium is 218 mmHg.

<u>For Part B:</u> The mass of helium gas is 0.504 g.

<u>Explanation:</u>

  • <u>For Part A:</u>

We are given:

p_{CO_2}=245mmHg\\p_Ar}=119mmHg\\p_{O_2}=163mmHg\\P=745mmHg

To calculate the partial pressure of helium, we use the formula:

P=p_{CO_2}+p_{Ar}+p_{O_2}+p_{He}

Putting values in above equation, we get:

745=245+119+163+p_{He}\\p_{He}=218mmHg

Hence, the partial pressure of Helium is 218 mmHg.

  • <u>For Part B:</u>

To calculate the mass of helium gas, we use the equation given by ideal gas:

PV = nRT

or,

PV=\frac{m}{M}RT

where,

P = Pressure of helium gas = 218 mmHg

V = Volume of the helium gas = 10.2 L

m = Mass of helium gas = ? g

M = Molar mass of helium gas = 4 g/mol

R = Gas constant = 62.3637\text{ L.mmHg }mol^{-1}K^{-1}

T = Temperature of helium gas = 283 K

Putting values in above equation, we get:

218mmHg\times 10.2L=\frac{m}{4g/mol}\times 62.3637\text{ L.mmHg }mol^{-1}K^{-1}\times 283K\\\\m=0.504g

Hence, the mass of helium gas is 0.504 g.

6 0
3 years ago
Question 1 of 15<br> 2 Points<br> What is another name for a pure substance?<br> Answer here
maksim [4K]

Answer:

element

Explanation:

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4 0
3 years ago
Consider the following data:
VikaD [51]

∆H ° rxn =-2855.56 kJ

<h3>Further explanation</h3>

Given

ΔHf CO₂ = -393.5 kJ/mol

ΔHf H₂O = -241.82 kJ/mol

ΔHf  C₂H₆ = - 84.68 kJ/mol

Reaction

2C2H6(g) + 7O2(g) -> 4CO2(g) + 6H2O(g)

Required

ΔHrxn=

Solution

<em>∆H ° rxn = ∑n ∆Hf ° (product) - ∑n ∆Hf ° (reactants) </em>

∆H ° rxn = (4.-393.5+6.-241.82)-(2.-84.68)

∆H ° rxn = (-1574-1450.92)-(-169.36)

∆H ° rxn =-3024.92+169.36

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8 0
3 years ago
Read 2 more answers
How can miscible liquids that different boiling points be separated
Afina-wow [57]

Answer:

By boiling and further condensing the liquid with the lowest boiling point.

Explanation:

Hello there!

In this case, according to the attached diagram, it turns out possible for us to infer that the mechanism whereby miscible liquids with different boiling points are separated is distillation, because the flask is heated until the boiling point of the liquid with the lowest value, in order to boil it and subsequently condense it, whereas the liquid with the highest boiling point remains in the flask; and therefore, the two liquids are separated.

Regards!

3 0
2 years ago
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