Answer:
168.0 g
Explanation:
First thing, write a balanced chemical equation:
n(H2SO4) = concentration * volume
= 1.0 M * 2.0 L
= 2.0 mol
According to the balanced equation, 1 mol of acid requires 2 mol of sodium bicarbonate. This means that 2 mol of acid requires 2 mol of sodium bicarbonate. What mass of sodium bicarbonate is this?
mass (NaHCO3) = number of moles * molar mass
= 2.0 mol * 84.0065 g/mol
= 168.0 g
Answer:
15.06 × 10²³ atoms of Li
Explanation:
Given data:
Number of moles of Li = 2.5 mol
Number of toms of Li = ?
Solution:
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 × 10²³ is called Avogadro number.
For example,
18 g of water = 1 mole = 6.022 × 10²³ molecules of water
1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen
For 2.5 mol of Li:
1 mole of lithium = 6.022 × 10²³ atoms of Li
2.5 mol × 6.022 × 10²³ atoms of Li / 1 mol
15.06 × 10²³ atoms of Li
7.04×10^14 is the frequencyof light by the relation:
wavelength= wave velocity/frequency
It is a simple stoichiometry problem. We have been given with balanced equation and 5.00 moles of HCl and have to calculate the moles of H2.
<span>From the balanced equation it is being clear that 2 moles of HCl are produced by 1 mole of H2. so, 1 mole of HCl will be produced by 1/2 moles of H2. So, the mole ratio of H2 and HCl is 1:2 </span>
<span>to calculate the moles of H2 for the given moles of HCl, multiply the moles of HCl by the mole ratio of H2 and HCl. </span>
<span>5.00 mole HCl x (1 mole H2/ 2 mole HCl) </span>
<span>= 2.50 mole H2 </span>
<span>so, to produce 5.00 moles of HCl, 2.50 moles of H2 are required.</span>
