I am not entirely sure but i believe the answer is C scupture
The correct answer is D: Watt. This unit was named after James Watt, and
is used to express the equivalent of one joule per second in energy. In
experiments and on the packaging for electrical products such as light-bulbs, the measurement will usually be written in its abbreviated
format: W.
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To solve the problem we will simply perform equivalence between both expressions. We will proceed to place your units and develop your internal operations in case there is any. From there we will compare and look at its consistency
![ma = \text{Mass}\times \text{Acceleration}](https://tex.z-dn.net/?f=ma%20%3D%20%5Ctext%7BMass%7D%5Ctimes%20%5Ctext%7BAcceleration%7D)
![ma = kg \cdot \frac{m}{s^2}](https://tex.z-dn.net/?f=ma%20%3D%20kg%20%5Ccdot%20%5Cfrac%7Bm%7D%7Bs%5E2%7D)
At the same time we have that
![\frac{1}{2}mv^2 = \text{Mass}\times \text{Velocity}^2](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7Dmv%5E2%20%3D%20%5Ctext%7BMass%7D%5Ctimes%20%5Ctext%7BVelocity%7D%5E2)
![\frac{1}{2}mv^2 = kg ( \frac{m}{s})^2](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7Dmv%5E2%20%3D%20kg%20%28%20%5Cfrac%7Bm%7D%7Bs%7D%29%5E2)
![\frac{1}{2}mv^2 = kg \cdot \frac{m^2}{s^2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7Dmv%5E2%20%3D%20kg%20%5Ccdot%20%5Cfrac%7Bm%5E2%7D%7Bs%5E2%7D)
Therefore there is not have same units and both are not consistent and the correct answer is B.
Initial speed = 2√10 m/s
<h3>Further explanation </h3>
Linear motion consists of 2: constant velocity motion with constant velocity and uniformly accelerated motion with constant acceleration
An equation of uniformly accelerated motion
V = vo + at
Vt² = vo² + 2a (x-xo)
x = distance on t
vo / vi = initial speed
vt / vf = speed on t / final speed
a = acceleration
vf=20 m/s
d = 60 m
a = 3 m/s²
![\tt vf^2=vi^2+2.ad\\\\20^2=vi^2+2\times 3\times 60\\\\400=vi^2+360\\\\40=vi^2\\\\vi=\sqrt{40}=2\sqrt{10}~m/s](https://tex.z-dn.net/?f=%5Ctt%20vf%5E2%3Dvi%5E2%2B2.ad%5C%5C%5C%5C20%5E2%3Dvi%5E2%2B2%5Ctimes%203%5Ctimes%2060%5C%5C%5C%5C400%3Dvi%5E2%2B360%5C%5C%5C%5C40%3Dvi%5E2%5C%5C%5C%5Cvi%3D%5Csqrt%7B40%7D%3D2%5Csqrt%7B10%7D~m%2Fs)
Why is it important that your finger be wet if you intend to touch it briefly to a hot clothes iron to test its temperature. If your finger is wet, some of the heat transmitted to your finger will be given to the water which has a high specific heat capacity and also a larger latent heat of vaporization.
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