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Nitella [24]
3 years ago
13

A chemist adds of a potassium permanganate solution to a reaction flask. Calculate the mass in grams of potassium permanganate t

he chemist has added to the flask. Round your answer to significant digits.
Chemistry
1 answer:
boyakko [2]3 years ago
6 0

Answer:

3.41 g

Explanation:

<em>A chemist adds 260.0 mL of a 0.0832M potassium permanganate solution to a reaction flask. Calculate the mass in grams of potassium permanganate the chemist has added to the flask. Round your answer to 3 significant digits.</em>

Step 1: Given data

Volume of the solution (V): 260.0 mL (0.2600 L)

Concentration of the solution (C): 0.0832 M (0.0832 mol/L)

Step 2: Calculate the moles (n) of potassium permanganate added

We will use the following expression.

n = C × V

n = 0.0832 mol/L × 0.2600 L = 0.0216 mol

Step 3: Calculate the mass corresponding to 0.0216 moles of potassium permanganate

The molar mass of potassium permanganate is 158.03 g/mol.

0.0216 mol × 158.03 g/mol = 3.41 g

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1. How many grams are there in 7.5 x 1023 molecules of H2SO4?
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I cannot give you all the answer but I can help you to solve those.

Explanation:

The first question:

How many grams are there in 7.5×10^{23} molecules of H_{2} SO_{4}?

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Then, we need to find how many moles, by using Avogadro's constant:

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-------------------------------------------------------------------------------------------------------------

In conclusion, use those formula to help you:

M= \frac{m}{n} (which M = molecular mass(atomic mass) m=mass of the substance and n = moles)

Avogadro's constant: \frac {molecular mass} {6.02*10^{23}} = moles

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