Which element has the same number of valence electrons as a krypton

Explain what happens to the sound waves when a singer hits the high pitched notes during the National Anthem. Be sure to use the

Tasya [4]

Answer: The frequency increases as the pitch increases, and the amplitude increases as the volume increases

Explanation:

Waves have the property of:

v = f*λ

where v is the speed of the wave (which is almost constant for soundwaves, v = 340 m/s)

f is the frequency of the wave, and λ is the wavelength.

Now, we know that when the pitch of a note increases, also does the frequency of the soundwave (so the wave oscillates faster).

Now, we also want to include the amplitude of the soundwave in this.

The amplitude is related to the volume of the soundwave (actually is related to the energy, and as higher is the energy, more "loud" is the sound).

As the high pitch part is usually "louder", we can assume that we have an amplitude increase.

Then the answer would be:

"The frequency increases as the pitch increases, and the amplitude increases as the volume increases"

4 0

3 years ago

A 10 kg runaway grocery cart runs into a spring with spring constant 250 n/m and compresses it by 60 cm. what was the speed of t

andrew-mc [135]

The initial kinetic energy of the cart is
$K= \frac{1}{2} mv^2$ (1)
where m is the mass of the cart and v its initial velocity.

Then, the cart hits the spring compressing it. The maximum compression occurs when the cart stops, and at that point the kinetic energy of the cart is zero, so all its initial kinetic energy has been converted into elastic potential energy of the spring:
$U= \frac{1}{2}kx^2$
where k is the spring constant and x is the spring compression.

For energy conservation, K=U. We can calculate U first: the compression of the spring is x=60 cm=0.60 m, while the spring constant is k=250 N/m, so
$U= \frac{1}{2}kx^2= \frac{1}{2}(250 N/m)(0.60 m)^2=45 J$

So, the initial kinetic energy of the cart is also 45 J, and from (1) we can find the value of the initial velocity:
$v= \sqrt{ \frac{2K}{m} }= \sqrt{ \frac{2 \cdot 45 J}{10 kg} } =3 m/s$

7 0

3 years ago

A car of weight 6,400 N has four wheels. Each wheel has an area of

Natasha2012 [34]

Answer:

80N/cm^2

Explanation:

Given data

A car of weight 6,400N

Area= 80cm^2

The weight is distributed evenly on the 4 wheels

hence 6400/4

=1600 N

We know that

Pressure = force/Area

Pressure= 1600/80

Pressure= 20 N/cm^2

For the four wheels, the pressure is

=20*4

=80N/cm^2

6 0

3 years ago

Explain why the liquid with the median density floats where it does

emmainna [20.7K]

Hey wats there answerssssssssssssss need it nowwwwwwww ASAP !!!!!!!

5 0

4 years ago

A laser dazzles the audience in a rock concert by emitting green light with a wavelength of 533 nm . Calculate the frequency of

atroni [7]

Answer:

f = 5.63 x 10¹⁴ Hz

Explanation:

Given,

speed of light, c = 3 x 10⁸ m/s

wavelength,λ = 533 n m = 5.33 x 10⁻⁷ m

frequency, f = ?

using formula of frequency

$f = \dfrac{c}{\lambda}$

c is the speed of light

$f = \dfrac{3\times 10^{8}}{5.33\times 10^{-7}}$

f = 5.63 x 10¹⁴ Hz

hence, the frequency of the light is equal to f = 5.63 x 10¹⁴ Hz

5 0

4 years ago