Answer:
Explanation:
From the question we are told that
The number of slits per cm is k = 
The order of the maxima is n = 1
The wavelength are 
The spacing between the slit is mathematically represented as
=> 
=> 
Generally the condition for constructive interference is
At 
![\theta _1 = sin^{-1} [ \frac{1 * 434 *10^{-9}}{6.211 *10^{-5}} ]](https://tex.z-dn.net/?f=%5Ctheta%20_1%20%20%3D%20%20sin%5E%7B-1%7D%20%5B%20%5Cfrac%7B1%20%20%2A%20%20434%20%2A10%5E%7B-9%7D%7D%7B6.211%20%2A10%5E%7B-5%7D%7D%20%5D)
At 
![\theta _2 = sin^{-1} [ \frac{1 * 410 *10^{-9}}{6.211 *10^{-5}} ]](https://tex.z-dn.net/?f=%5Ctheta%20_2%20%20%3D%20%20sin%5E%7B-1%7D%20%5B%20%5Cfrac%7B1%20%20%2A%20%20410%20%2A10%5E%7B-9%7D%7D%7B6.211%20%2A10%5E%7B-5%7D%7D%20%5D)
Answer:
The smallest possibility is 0.01E-22kgm/s
Explanation:
Using
Momentum= h/4πx
= 6.6x 10^-34Js/ 4(3.142* 50*10-12m)
= 0.01*10^-22kgm/s
Answer:
130N
Explanation:
F<em>=</em><em>(</em><em>M1+</em><em>M</em><em>2</em><em>)</em><em>V</em>
<em>F=</em><em> </em><em>(</em><em>7</em><em>0</em><em>+</em><em>6</em><em>0</em><em>)</em><em>*</em><em>1</em>
<em>F=</em><em>1</em><em>3</em><em>0</em><em>*</em><em>1</em>
<em>F=</em><em>1</em><em>3</em><em>0</em><em>N</em><em>/</em><em>/</em>
Answer:
F' = (4/9)F
Explanation:
The electrostatic force between two charged objects is given by Coulomb's Law:
F = kq₁q₂/r² -------------------- equation (1)
where,
F = Electrostatic Force
k = Coulomb's Constant
q₁ = magnitude of first charge
q₂ = magnitude of second charge
r = distance between charges
Now, when the charges and distance altered as follows:
q₁' = 2q₁
q₂' = 2q₂
r' = 3r
Then,
F' = kq₁'q₂'/r'²
F' = k(2q₁)(2q₂)/(3r)²
F' = (4/9)kq₁q₂/r²
using equation (1):
<u>F' = (4/9)F</u>
