Answer:
speed of plane in still air = 1060 km/h
speed of wind = 170 km/h
Explanation:
Let teh speed of plane in still air is vp and the speed of air is va.
Irt travels 2670 km in 3 hours against the wind
So,
vp - va = 2670 / 3 = 890 km/h ..... (1)
It travels 11070 km in 9 hours along the wind.
vp + va = 11070 / 9 = 1230 km/h .... (2)
Adding both the equations
2 vp = 2120
vp = 1060 km/h
and va = 1230 - vp = 1230 - 1060 = 170 km/h
1. liquid solution to a. oceans
2. gaseous solution to b. clouds
Not sure about 3 and 4.
3 might be oxygen but I think that's 5. element.
Hope this helps, not sure about water and air though.
Answer:
v = 1.6 m/s
Explanation:
Given that,
Distance, d = 72 m
Time taken, t = 45 s
We need to find their average velocity. Average velocity of an object is given by total distance divided by total time taken.
So, their average velocity is 1.6 m/s.
Answer:
Explanation:
The experimenter is rotating on his stool with angular velocity ω ( suppose )
His moment of inertia is I say
We are applying no torque from outside . therefore , the angular momentum will remain the same
Thus angular momentum L = I ω = constant
Thus we can say I₁ ω₁ = I₂ω₂ = constant
here I₁ is the initial moment of inertia and ω₁ is the initial angular velocity
Similarly I₂ is the final moment of inertia and ω₂ is the final angular velocity
When a been bag is dropped on his lap , his moment of inertia increases due to increase in mass
In the above equation, when moment of inertia increases , the angular velocity decreases . So its motion of rotation will decrease .
The block with the bullet lodged in the block is now travelling at 2.133 m/s.
<h3>What is momentum conservation principle?</h3>
When there is no external force acting on the system, the momentum remains conserved.
For inelastic collision, after collision both objects travel with common speed.
m1u1 + m2u2 =(m1 +m2)v
Substitute initial velocity of bullet u1 =320 m/s , initial velocity of block u2 =0, mass of bullet m1 = 0.1 kg and mass of block m2 = 14.9 kg.
Solve for the final velocity of bullet,
0.1 x 320 + 14.9 x 0 = (0.1 +14.9) x v
v = 2.133 m/s
Thus, the block with the bullet lodged in block now travelling at 2.133 m/s.
Learn more about momentum conservation principle.
brainly.com/question/14033058
#SPJ1
