Answer:
Rage :)
Raging lets ur anger out :)
Answer:
Speed will be equal to 1.40 m/sec
Explanation:
Mass of the rubber ball m = 5.24 kg = 0.00524 kg
Spring is compressed by 5.01 cm
So x = 5.01 cm = 0.0501 m
Spring constant k = 8.08 N/m
Frictional force f = 0.031 N
Distance moved by ball d = 15.8 cm = 0.158 m
Energy gained by spring
![KE=\frac{1}{2}kx^2=\frac{1}{2}\times 8.08\times 0.0501^2=0.0101J](https://tex.z-dn.net/?f=KE%3D%5Cfrac%7B1%7D%7B2%7Dkx%5E2%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%208.08%5Ctimes%200.0501%5E2%3D0.0101J)
Energy lost due to friction
![W=Fd=0.031\times 0.158=0.0048J](https://tex.z-dn.net/?f=W%3DFd%3D0.031%5Ctimes%200.158%3D0.0048J)
So remained energy to move the ball = 0.0101 - 0.0048 = 0.0052 J
This energy will be kinetic energy
![\frac{1}{2}mv^2=0.0052](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7Dmv%5E2%3D0.0052)
![\frac{1}{2}\times 0.00524\times v^2=0.0052](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5Ctimes%200.00524%5Ctimes%20v%5E2%3D0.0052)
v = 1.40 m/sec
Answer:
Frequency of incident light = 995×10 12
Explanation:
hope this helped you :)
Answer:
C I think so
Explanation:
ocean waves hitting a concert barrier that reduces their energy
F- force on the object,
m - mass of the object:
F = 12 N = 12 kgm/s², m = 2 kg
F = m · a
a = F : m = 12 N : 2 kg = 6 m/s²
Answer: C)