Ask question

Ask question

All categories

1 year ago

6

A function is different from a procedure because a functiondoes not contain a set of instructions.can have only a limited number

of steps.returns a value.is mathematical.

2 answers:

Sonja [21]1 year ago

8 0

Answer:

c - returns a value.

Explanation:

on edge pls mark brainiest

777dan777 [17]1 year ago

6 0

Answer: A function returns a value and a procedure just executes commands.

Explanation:

You might be interested in

A colorful design for a product meant to appeal to a preschool audience reflects which of the following points in industrial des

lord [1]

Appeal to emotion

the product doesn’t need to be colorful to function but it would be more appealing to the intended audience if it was

6 0

2 years ago

Phil wants to make a dark themed superhero movie. What could be his target demographic?

grin007 [14]

Answer:

D.

male, aged 18-25

5 0

2 years ago

Read 2 more answers

When a rubber is stretched during a tensile test, its elongation is initially proportional to the applied force, but as it reach

Softa [21]

I don’t feel like reading

4 0

2 years ago

The exhaust steam from a power station turbine is condensed in a condenser operating at 0.0738 bar(abs). The surface of the heat

lozanna [386]

Answer:

Percentage change 5.75 %.

Explanation:Given ;

Given

Pressure of condenser =0.0738 bar

Surface temperature=20°C

Now from steam table

Properties of steam at 0.0738 bar

Saturation temperature corresponding to saturation pressure =40°C

$h_f= 167.5\frac{KJ}{Kg},h_g= 2573.5\frac{KJ}{Kg}$

So Δh=2573.5-167.5=2406 KJ/kg

Enthalpy of condensation=2406 KJ/kg

So total heat=Sensible heat of liquid+Enthalpy of condensation

$Total\ heat\ =C_p\Delta T+\Delta h$

Total heat =4.2(40-20)+2406

Total heat=2,544 KJ/kg

Now film coefficient before inclusion of sensible heat

$h_1=\dfrac{\Delta h}{\Delta T}$

$h_1=\dfrac{2406}{20}$

$h_1=120.3\frac{KJ}{kg-m^2K}$

Now film coefficient after inclusion of sensible heat

$h_2=\dfrac{total\ heat}{\Delta T}$

$h_2=\dfrac{2,544}{20}$

$h_2=127.2\frac{KJ}{kg-m^2K}$

$So\ Percentage\ change=\dfrac{h_2-h_1}{h_1}\times 100$

$=\dfrac{127.2-120.3}{120.3}\times 100$

=5.75 %

So Percentage change 5.75 %.

3 0

2 years ago

What measures can be taken to mitigate or prevent the formation of stress corrosion cracks?

sasho [114]

Answer:

a) Selection and control of material

b) Control of stress

c) Control of the environment

Explanation:

The measures that can be taken to control and prevent the formation of strss corrosion cracks are:

a) Selection and control of material

It deals with the selection of the best quality material that can resist the stress corrosion cracks to a high extent.

b) Control of stress

It is to control or reduce the intensity of the major stress that causes the stress corrosion cracks.

c) Control of the environment

It includes the prevention of the material from the corrosive environment by removing the component from the region or controlling the environment condition around the object.

7 0

3 years ago