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3 years ago

6

A function is different from a procedure because a functiondoes not contain a set of instructions.can have only a limited number

of steps.returns a value.is mathematical.

2 answers:

Sonja [21]3 years ago

8 0

Answer:

c - returns a value.

Explanation:

on edge pls mark brainiest

777dan777 [17]3 years ago

6 0

Answer: A function returns a value and a procedure just executes commands.

Explanation:

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The room temperature electrical conductivity of a semiconductor specimen is 2.8 x 10^4 (Ω-m)1. The electron concentration is kno

dimaraw [331]

Given:

$\sigma _{s} = 2.8\times 10^{4} \Omega-m$

electron concentration, n = $2.9\times 10^{22} m^{-3}$

$\mu _{h} = 0.14$

$\mu _{e} = 0.023$

Solution:

Let holes concentration be 'p'

$\sigma _{s}$ = ne $\mu _{e}$ +pe $\mu _{h}$ (1)

substituting all given values in eqn (1):

$2.8\times 10^{4} = 2.9\times 10^{22}\times 1.6 \times 10^{-19}\times 0.14 + p\times1.6 \times 10^{-19}\times 0.023$

The cocentration of holes is:

$p = 7.432\times 10^{24} m^{-3}$

6 0

3 years ago

A shaft consisting of a steel tube of 50-mm outer diameter is to transmit 100 kW of power while rotating at a frequency of 34 Hz

nikitadnepr [17]

Answer:

25 - $\sqrt[4]{26.66*10^{-8} }$ mm

Explanation:

Given data

steel tube : outer diameter = 50-mm

power transmitted = 100 KW

frequency(f) = 34 Hz

shearing stress ≤ 60 MPa

Determine tube thickness

firstly we calculate the ; power, angular velocity and torque of the tube

power = T(torque) * w (angular velocity)

angular velocity ( w ) = 2 $\pi$ f = 2 * $\pi$ * 34 = 213.71

Torque (T) = power / angular velocity = 100000 / 213.71 = 467.92 N.m/s

next we calculate the inner diameter using the relation

$\frac{J}{c_{2} } = \frac{T}{t_{max} }$ = 467.92 / (60 * 10^6) = 7.8 * 10^-6 m^3

also

c2 = (50/2) = 25 mm

$\frac{J}{c_{2} }$ = $\frac{\pi }{2c_{2} } ( c^{4} _{2} - c^{4} _{1} )$ = $\frac{\pi }{0.050} [ ( 0.025^{4} - c^{4} _{1} ) ]$

therefore; 0.025^4 - $c^{4} _{1}$ = 0.050 / $\pi$ (7.8 *10^-6)

$c^{4} _{1}$ = 39.06 * 10 ^-8 - ( 1.59*10^-2 * 7.8*10^-6)

39.06 * 10^-8 - 12.402 * 10^-8 =26.66 *10^-8

$c_{1} = \sqrt[4]{26.66 * 10^{-8} }$ =

THE TUBE THICKNESS

$c_{2} - c_{1}$ = 25 - $\sqrt[4]{26.66*10^{-8} }$ mm

4 0

4 years ago

For this given problem, if the yield strength is now 45 ksi, using Distortion Energy Theory the material will _______ and using

serious [3.7K]

Answer:

Option A - fail/ not fail

Explanation:

For this given problem, if the yield strength is now 45 ksi, using Distortion Energy Theory the material will _fail______ and using the Maximum Shear Stress Theory the material will ___not fail_______

6 0

4 years ago

Waterbutt filtration system for pond. Water pressure principles, help needed?

shepuryov [24]

Water pressure principles is known to state that the amount of Fluid pressure is said to be perpendicular to the surface on which it it exert or works on.

Note that principle is shown by a vessel that is said to be having flat sides and has water. The pressure exerted by the weight of the water is therefore known to be perpendicular to the walls of the storage.

<h3>What is a Waterbutt used for?</h3>

A water butt is known to be a container that is made and also used to store a lot of rainwater.

Note that Water pressure principles is known to state that the amount of Fluid pressure is said to be perpendicular to the surface on which it it exert or works on.

Learn more about Water pressure principles from

brainly.com/question/14813457

#SPJ1

6 0

2 years ago

Suppose we want to determine how many of the bits in a twelve-bit unsigned number are equal to zero. Implement the simplest circ

timurjin [86]

Answer:

See the picture for circuit figure.

Explanation:

First load 12 bit unsigned number on shift register and apply clock tick to increment counter from LSB bit.

Logic 1 is shifted into register to ensure counter doesn't count more than 12 bits.

8 0

3 years ago