48/64 reduced to its lowest term
2 answers:
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Answer:
The answer is below
Explanation:
Given that:
ρ = 800 kg/m3, c = 600 J/kg-K, k = 40 W/m-K, Initial temperature = Ti = 1150,
Environment temperature = T = 450 K, Final temperature = T∞ = 325 K
Diameter = 10 mm = 0.01 m, A = 6
The estimated time for cooling process (t) is given as:
The estimated cooling time is 589 s
Answer:
1121.7 × 10³⁰ photons per second
Explanation:
Data provided in the question:
Power transmitted by the AM radio,P = 550 kW = 550 × 10³ W
Frequency of AM radio, f = 740 kHz = 740 × 10³ Hz
Now,
P =
here,
N is the number of photons
t is the time
E = energy = hf
h = plank's constant = 6.626 × 10⁻³⁴ m² kg / s
Thus,
P = =
[t = 1 s for per second]
or
550 × 10³ =
or
550 = N × 4903.24 × 10⁻³⁴
or
N = 0.11217 × 10³⁴ = 1121.7 × 10³⁰ photons per second