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2 years ago

12

Find the resolving power of a Fabry-Perot interferometer in which two silver coated plates have reflectance of ???? = 0.9, if th

e plate separation is 1 cm and the wavelength is 500 nm.

1 answer:

pochemuha2 years ago

7 0

Answer:

Resolving Power=625000

Explanation:

See attached picture.

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What other ways could a wildfire be contained, extinguished, or slowed down?

galben [10]

Back burning, starting fires infront of the main fire to prevent the fire from spreading and depleting fuel for the fire, digging trenches so the fire has no where to go, dropping water from planes or helicopters.

3 0

2 years ago

The accompanying specific gravity values describe various wood types used in construction. 0.320.350.360.360.370.380.400.400.40

marysya [2.9K]

Answer:

$\begin{array}{ccc}{Steam} & {\vert} & {Leaf} \ \\ \\ {0.3} & {\vert} & {2\ 5\ 6\ 6\ 7\ 8} \ \\ \\{0.4} & {\vert} & {0\ 0\ 0\ 1\ 1\ 2\ 2\ 2\ 2\ 2\ 3\ 4\ 5\ 6\ 6\ 7\ 8\ 8\ 9} \ \\ \ \\ {0.5} & {\vert} & {1\ 4\ 4\ 5\ 8} \ \\ \ \\ {0.6} & {\vert} & {3\ 6\ 6\ 7\ 8} \ \\ \ \\ {0.7} & {\vert} & {8} \ \ \end{array}$

Explanation:

Given

$0.32,\ 0.35,\ 0.36,\ 0.36,\ 0.37,\ 0.38,\ 0.40,\ 0.40,\ 0.40,\ 0.41,$

$0.41,\ 0.42,\ 0.42,\ 0.42,\ 0.42,\ 0.42,\ 0.43,\ 0.44,\ 0.45,\ 0.46,$

$0.46,\ 0.47,\ 0.48,\ 0.48,\ 0.49,\ 0.51,\ 0.54,\ 0.54,\ 0.55,$

$0.58,\ 0.63,\ 0.66,\ 0.66,\ 0.67,\ 0.68,\ 0.78.$

Required

Plot a steam and leaf display for the given data

Start by categorizing the data by their tenth values:

$0.32,\ 0.35,\ 0.36,\ 0.36,\ 0.37,\ 0.38.$

$0.40,\ 0.40,\ 0.40,\ 0.41,\ 0.41,\ 0.42,\ 0.42,\ 0.42,\ 0.42,\ 0.42,$

$0.43,\ 0.44,\ 0.45,\ 0.46,\ 0.46,\ 0.47,\ 0.48,\ 0.48,\ 0.49.$

$0.51,\ 0.54,\ 0.54,\ 0.55,\ 0.58.$

$0.63,\ 0.66,\ 0.66,\ 0.67,\ 0.68.$

$0.78.$

The 0.3's is will be plotted as thus:

$\begin{array}{ccc}{Steam} & {\vert} & {Leaf} \ \\ {0.3} & {\vert} & {2\ 5\ 6\ 6\ 7\ 8} \ \ \end{array}$

The 0.4's is as follows:

$\begin{array}{ccc}{Steam} & {\vert} & {Leaf} \ \\ {0.4} & {\vert} & {0\ 0\ 0\ 1\ 1\ 2\ 2\ 2\ 2\ 2\ 3\ 4\ 5\ 6\ 6\ 7\ 8\ 8\ 9} \ \ \end{array}$

The 0.5's is as follows:

$\begin{array}{ccc}{Steam} & {\vert} & {Leaf} \ \\ {0.5} & {\vert} & {1\ 4\ 4\ 5\ 8} \ \ \end{array}$

The 0.6's is as thus:

$\begin{array}{ccc}{Steam} & {\vert} & {Leaf} \ \\ {0.6} & {\vert} & {3\ 6\ 6\ 7\ 8} \ \ \end{array}$

Lastly, the 0.7's is as thus:

$\begin{array}{ccc}{Steam} & {\vert} & {Leaf} \ \\ {0.7} & {\vert} & {8} \ \ \end{array}$

The combined steam and leaf plot is:

$\begin{array}{ccc}{Steam} & {\vert} & {Leaf} \ \\ \\ {0.3} & {\vert} & {2\ 5\ 6\ 6\ 7\ 8} \ \\ \\{0.4} & {\vert} & {0\ 0\ 0\ 1\ 1\ 2\ 2\ 2\ 2\ 2\ 3\ 4\ 5\ 6\ 6\ 7\ 8\ 8\ 9} \ \\ \ \\ {0.5} & {\vert} & {1\ 4\ 4\ 5\ 8} \ \\ \ \\ {0.6} & {\vert} & {3\ 6\ 6\ 7\ 8} \ \\ \ \\ {0.7} & {\vert} & {8} \ \ \end{array}$

8 0

2 years ago

How to measure the quality of the output signal in ADC?

hodyreva [135]

Answer:

C. Signal-to-quantization-noise ratio

Explanation:

8 0

2 years ago

Question 29: Returns a string based on input string The function below takes a single string parameter: input_string. If the inp

kirill [66]

Answer:

Two Python codes are explained for the problem. Modify as appropriate

Explanation:

<u>CODE 1:</u>

def string_contains(input_string): # called function

if(input_string.__contains__('z')): # Check input_string contains 'z'

print('has the letter z.') # print input_string contains 'z'

else:

print('not worthwhile.') # print if input_string not contains 'z'

input_string = input('Please enter the string: ') # ACeept string from user

string_contains(input_string) # calling function where we pass input_string as actual parameter

<u>CODE 2:</u>

def string_contains(input_string):

for x in input_string:

if x=='z':

return 'has the letter z'

return 'not worthwhile'

8 0

2 years ago

1. The area(in square centimeters) of a square coaster can be represented by

Brrunno [24]

Answer: (d−4) 2

Explanation: Factoring d2-8d+16

The first term is, d2 its coefficient is 1 .

The middle term is, -8d its coefficient is -8 .

The last term, "the constant", is +16

Step-1 : Multiply the coefficient of the first term by the constant 1 • 16 = 16

Step-2 : Find two factors of 16 whose sum equals the coefficient of the middle term, which is -8 .

-16 + -1 = -17

-8 + -2 = -10

-4 + -4 = -8 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -4 and -4

d2 - 4d - 4d - 16

Step-4 : Add up the first 2 terms, pulling out like factors :

d • (d-4)

Add up the last 2 terms, pulling out common factors :

4 • (d-4)

Step-5 : Add up the four terms of step 4 :

(d-4) • (d-4)

Which is the desired factorization

Multiply (d-4) by (d-4)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is (d-4) and the exponents are :

1 , as (d-4) is the same number as (d-4)1

and 1 , as (d-4) is the same number as (d-4)1

The product is therefore, (d-4)(1+1) = (d-4)2

Please mark me brainlyest

7 0

2 years ago