1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alenkinab [10]
3 years ago
6

Which metals may be oxidized by H+ under standard-state conditions? Ag+(aq) + e– → Ag(s) E° = 0.80 V Cu2+(aq) + 2e– → Cu(s) E° =

0.34 V Sn2+(aq) + 2e– → Sn(s) E° = –0.14 V Zn2+(aq) + 2e– → Zn(s) E° = –0.76 V
Chemistry
1 answer:
Debora [2.8K]3 years ago
8 0
Answer is: tin and zinc, because they standard potential as less than zero.
Tin and zinc are oxidized to tin and zinc cations (with +2 charge) and hydrogen anions are reduced to hydrogen molecules with neutral charge.
Zn → Zn²⁺ + 2e⁻; 2H⁺ + 2e⁻ → H₂.
<span>Oxidation is increase of oxidation number  and reduction is decrease of oxidation number.</span>
You might be interested in
What caused our solar system to form by pulling together gases and dust in a nebula?​
Furkat [3]
I’m pretty sure it’s gravity man
5 0
2 years ago
Converting the following mm Hg (torr) to standard
11Alexandr11 [23.1K]

Explanation:

Given:

20.5 torr

78.6 torr

225 torr

Change into atm

Computation:

We know that;

1 torr = 0.00131579 atm

So,

1. 20.5 torr

= 20.5 x 0.00131579 atm

= 0.02697

= 0.027 atm (Approx)

2. 78.6 torr

= 78.6 x 0.00131579 atm

= 0.103090

= 0.103 atm (Approx)

3. 225 torr

= 225 x 0.00131579 atm

= 0.2960

= 0.296 atm (Approx)

5 0
3 years ago
Help with a and b if so thanks please asap!!
Anastaziya [24]

Answer:

A.  0.01  B. 650

Explanation:

I love helping people.

7 0
4 years ago
Can Someone help me with this ​
vodomira [7]

Answer:

1. Mg²⁺   2. Cl⁻    3. PO₄³⁻

Explanation:

6 0
3 years ago
Read 2 more answers
Determine the number of shared and unshared electrons in the structure. shared (bonding) electrons: unshared (lone, nonbonding)
telo118 [61]

This is an incomplete question, here is a complete question.

The given molecule is, SO_3 and structure is shown below.

Determine the number of shared and unshared electrons in the structure.

Shared (bonding) electrons :

Unshared (lone, non-bonding) electrons :

Answer :

Shared (bonding) electrons : 8

Unshared (lone, non-bonding) electrons : 16

Explanation :

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

The given molecule is, SO_3

As we know that sulfur and oxygen has '6' valence electrons.

Therefore, the total number of valence electrons in SO_3 = 6 + 3(6) = 24

Bonding electrons : These are those electrons that are shared between the atoms resulting in the formation of bond.

Non-bonding electrons : They are the valence electrons of the atom which are not shared with another atom.

According to Lewis-dot structure, there are 8 number of bonding electrons and 16 number of non-bonding electrons.

4 0
3 years ago
Other questions:
  • HELP TIMED !!!!
    9·2 answers
  • Calculate the mass of 0.00456 moles of (NH4)2SO4
    10·1 answer
  • And Adam that has fewer neutrons then protons and more electrons than protons is a
    9·1 answer
  • Which phrase is an example of what electrostatic forces hold together?
    15·1 answer
  • Using the Mohs standard hardness scale, which of the following scratch tests is correct? Scale Mineral 10 diamond 9 corundum 8 t
    10·2 answers
  • The air exhaled from the lungs of a smoker has a concentration of 24 ppm CO. Express the concentration as a percent.
    13·1 answer
  • GIVING 5 STARS AND BRAINLY IF YOU ANSWER FIRST AND CORRECTLY
    11·1 answer
  • What 2 solutions could help restore the ecosystem back to normal?
    7·1 answer
  • Does jailbreaking an ipad will have more virus on it yes or no,explain?
    11·2 answers
  • It is economical to use scrap iron to get copper.<br> Give one reason why.
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!