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cricket20 [7]
1 year ago
13

A motor has coils with a resistance of 10.0 ohms and is supplied by a voltage of V = 1.20 x 102 V. When the motor is running at

its maximum speed, the back emf is 70.0 V. Find the current in the coils (a) when the motor is first turned on and (b) when the motor has reached its maximum rotation rate.
Physics
1 answer:
Vanyuwa [196]1 year ago
8 0

Hi there!

a)
When the motor is first turned on, the coils are initially stationary. Thus, there is no change in magnetic flux and, consequently, no induced emf.

Therefore:
iR = \epsilon - \epsilon_{back}

Since there's no back emf:
iR = \epsilon

Solving for i using Ohm's Law:
i = \frac{\epsilon}{R}\\\\i = \frac{120}{10} = \boxed{12.0 A}

b)

We are given that at max speed, the back EMF is 70.0 V.

Using the same equation as above:
iR = \epsilon - \epsilon_{back}

Plugging in the values:
10i = 120 - 70 \\\\10i = 50 \\\\

Solving for current:
i = \frac{50}{10} = \boxed{ 5.0 A}

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Answer:

B)

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2 years ago
A 4.0 m length of gold wire is connected to a 1.5 V battery, and a current of 4.0 mA flows through it. What is the diameter of t
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Explanation:

Given that,

Length of gold wire, l = 4 m

Voltage of battery, V = 1.5 V

Current, I = 4 mA

The resistivity of gold, \rho=2.44\times 10^{-8}\ \Omega-m

Resistance in terms of resistivity is given by :

R=\dfrac{\rho l}{A}

Also, V = IR

So,

\dfrac{V}{I}=\dfrac{\rho l}{A}

A is area of wire,

\dfrac{V}{I}=\dfrac{\rho l}{\pi r^2}, r is radius, r = d/2 (diameter=d)

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