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cricket20 [7]
2 years ago
13

A motor has coils with a resistance of 10.0 ohms and is supplied by a voltage of V = 1.20 x 102 V. When the motor is running at

its maximum speed, the back emf is 70.0 V. Find the current in the coils (a) when the motor is first turned on and (b) when the motor has reached its maximum rotation rate.
Physics
1 answer:
Vanyuwa [196]2 years ago
8 0

Hi there!

a)
When the motor is first turned on, the coils are initially stationary. Thus, there is no change in magnetic flux and, consequently, no induced emf.

Therefore:
iR = \epsilon - \epsilon_{back}

Since there's no back emf:
iR = \epsilon

Solving for i using Ohm's Law:
i = \frac{\epsilon}{R}\\\\i = \frac{120}{10} = \boxed{12.0 A}

b)

We are given that at max speed, the back EMF is 70.0 V.

Using the same equation as above:
iR = \epsilon - \epsilon_{back}

Plugging in the values:
10i = 120 - 70 \\\\10i = 50 \\\\

Solving for current:
i = \frac{50}{10} = \boxed{ 5.0 A}

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14. measuring cylinder containing some water stands on a scale pan. A solid ball is lowered into the water. The water level rise
Basile [38]

Answer:

Let d be the density of fluid.

So , Initial reading of balance, F1 =30dg N

After the level reaches 50cm^3

Final reading of balance , F2 =50dg N

Given that difference between final and initial reading is 30g

i.e, F2 −F1

=30 g

⟹50dg−30dg=30g

⟹20dg=30g

⟹d=30g/20g

⟹d=1.5g/cm^3

So, density of fluid is 1.5g/cm^3

8 0
3 years ago
Plz help, and show work
pentagon [3]

Answer:

1. 2.67 s

2. 0.1 m/s²

Explanation:

1. Determination of the time taken for the penguin to fall.

Height (h) of cliff = 35 m

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =?

h = ½gt²

35 = ½ × 9.8 × t²

35 = 4.9 × t²

Divide both side by 4.9

t² = 35 / 4.9

Take the square root of both side

t = √(35 / 4.9)

t = 2.67 s

Thus, it will take 2.67 s for the penguin to fall onto the head of a napping polar bear.

2. Determination of the acceleration of the penguin.

Initial velocity (u) = 0 m/s.

Final velocity (v) = 2 m/s.

Time (t) = 20 s

Acceleration (a) =?

a = (v – u)/t

a = (2 – 0)/ 20

a = 2 / 20

a = 0.1 m/s²

Thus, the acceleration of the penguin is 0.1 m/s²

8 0
2 years ago
if something is shot straight up in the air at a speed of 17 m/s, how much time before I it will hit the ground ​
wolverine [178]
About 17.2 square feet of inches
8 0
2 years ago
I NEED HELP!!!!!!!!!!!
nadezda [96]

1. 168.1 Hz

To find the apparent frequency heard by the driver in the car, we can use the formula for the Doppler effect:

f'=(\frac{v\pm v_o}{v\pm v_s})f

where

f is the original sound of the horn

v is the speed of sound

v_o is the velocity of the observer (the driver and the car), which is positive if the observer is moving towards the source and negative if it is moving away

v_s is the velocity of the sound source (the train), which is positive if the source is moving away from the observer and negative otherwise

In this problem we have, according to the sign convention used:

v = 343 m/s\\f = 164 Hz\\v_o = -15 m/s\\v_s = -23 m/s

Substituting, we find:

f'=(\frac{343-15}{343-23})(164)=168.1 Hz

2.  2.96\cdot 10^8 m/s

The speed of light can be calculated as

v=\frac{d}{t}

where

d is the distance travelled

t is the time taken

In this problem:

d=2\cdot 3.85\cdot 10^8 =7.7\cdot 10^8 m is the total distance travelled by the laser beam (twice the distance between the Earth and the Moon)

t = 2.60 s is the time taken

Substituting in the formula,

v=\frac{7.7\cdot 10^8 m}{2.60 s}=2.96\cdot 10^8 m/s

6 0
3 years ago
Using a scale diagram, calculate the resultant force acting on a sailing boat when an easterly wind provides 2, point, 50, k, N,
EastWind [94]

Answer:

F = 3.6 kN, direction is 9.6º to the North - East

Explanation:

The force is a vector, so one method to find the solution is to work with the components of the vector as scalars and then construct the resulting vector.

Let's use trigonometry to find the component of the forces, let's use a reference frame where the x-axis coincides with the East and the y-axis coincides with the North.

Wind

X axis

          F₁ = 2.50 kN

Tide

         cos 30 = F₂ₓ / F₂

         sin 30 = F_{2y} / F₂

          F₂ₓ = F₂ cos 30

         F_{2y} = F₂ sin 30

         F₂ₓ = 1.20cos 30 = 1.039 kN

         F_{2y} = 1.20 sin 30 = 0.600 kN

the resultant force is

X axis

        Fₓ = F₁ₓ + F₂ₓ

        Fₓ = 2.50 +1.039

        Fₓ = 3,539 kN

        F_y = F_{2y}

        F_y = 0.600

to find the vector we use the Pythagorean theorem

         F = \sqrt{F_x^2 +F_y^2}

         F = \sqrt{ 3.539^2 + 0.600^2 }

         F = 3,589 kN

the address is

         tan θ = F_y / Fₓ

         θ = tan⁻¹ \frac{F_y}{F_x}

         θ = tan⁻¹  \frac{0.6}{3.539}0.6 / 3.539

         θ = 9.6º

the resultant force to two significant figures is

         F = 3.6 kN

the direction is 9.6º to the North - East

7 0
3 years ago
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