Answer:
Let d be the density of fluid.
So , Initial reading of balance, F1 =30dg N
After the level reaches 50cm^3
Final reading of balance , F2 =50dg N
Given that difference between final and initial reading is 30g
i.e, F2 −F1
=30 g
⟹50dg−30dg=30g
⟹20dg=30g
⟹d=30g/20g
⟹d=1.5g/cm^3
So, density of fluid is 1.5g/cm^3
Answer:
1. 2.67 s
2. 0.1 m/s²
Explanation:
1. Determination of the time taken for the penguin to fall.
Height (h) of cliff = 35 m
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) =?
h = ½gt²
35 = ½ × 9.8 × t²
35 = 4.9 × t²
Divide both side by 4.9
t² = 35 / 4.9
Take the square root of both side
t = √(35 / 4.9)
t = 2.67 s
Thus, it will take 2.67 s for the penguin to fall onto the head of a napping polar bear.
2. Determination of the acceleration of the penguin.
Initial velocity (u) = 0 m/s.
Final velocity (v) = 2 m/s.
Time (t) = 20 s
Acceleration (a) =?
a = (v – u)/t
a = (2 – 0)/ 20
a = 2 / 20
a = 0.1 m/s²
Thus, the acceleration of the penguin is 0.1 m/s²
1. 168.1 Hz
To find the apparent frequency heard by the driver in the car, we can use the formula for the Doppler effect:

where
f is the original sound of the horn
v is the speed of sound
is the velocity of the observer (the driver and the car), which is positive if the observer is moving towards the source and negative if it is moving away
is the velocity of the sound source (the train), which is positive if the source is moving away from the observer and negative otherwise
In this problem we have, according to the sign convention used:

Substituting, we find:

2. 
The speed of light can be calculated as

where
d is the distance travelled
t is the time taken
In this problem:
is the total distance travelled by the laser beam (twice the distance between the Earth and the Moon)
t = 2.60 s is the time taken
Substituting in the formula,

Answer:
F = 3.6 kN, direction is 9.6º to the North - East
Explanation:
The force is a vector, so one method to find the solution is to work with the components of the vector as scalars and then construct the resulting vector.
Let's use trigonometry to find the component of the forces, let's use a reference frame where the x-axis coincides with the East and the y-axis coincides with the North.
Wind
X axis
F₁ = 2.50 kN
Tide
cos 30 = F₂ₓ / F₂
sin 30 = F_{2y} / F₂
F₂ₓ = F₂ cos 30
F_{2y} = F₂ sin 30
F₂ₓ = 1.20cos 30 = 1.039 kN
F_{2y} = 1.20 sin 30 = 0.600 kN
the resultant force is
X axis
Fₓ = F₁ₓ + F₂ₓ
Fₓ = 2.50 +1.039
Fₓ = 3,539 kN
F_y = F_{2y}
F_y = 0.600
to find the vector we use the Pythagorean theorem
F = 
F = 
F = 3,589 kN
the address is
tan θ = F_y / Fₓ
θ = tan⁻¹
θ = tan⁻¹
0.6 / 3.539
θ = 9.6º
the resultant force to two significant figures is
F = 3.6 kN
the direction is 9.6º to the North - East