well if i am not mistaken it is true. i just did the the class and yes its true i just looked back.
thanks for asking your question on brainly have a nice day:D
<span>crunching and folds the rock at the boundary, lifts it up and leads to the formation of mountains </span>
Answer:
We can separate AgCl and PbCl₂ by adding hot water.
Explanation:
In order to separate group one salts/ions is important to consider their solubility.
PbCl₂ is more soluble in water then AgCl and, when we increase water's temperature, PbCl₂ solubility icireases significantly. However, AgCl solubility does not change considerably.
Therefore, when we add hot water to the solution, the PbCl₂ will be dissolved and AgCl will remain as a precipitate.
Answer:
- 278.85 J
Explanation:
Given that:
Pressure = 1.1 atm
The initial volume V₁ = 0.0 L
The final volume V₂ = 2.5 L
The work that takes place in a reaction at constant pressure can be expressed by using the equation:
W = P(V₂ - V₁ )
Since the volume of the gas is expanded from 0 to 2.5 L when 1.1 atm pressure is applied. Then, the work can be given by the expression:
W = - P(V₂ - V₁ )
W = -1.1 atm ( 2.5 - 0.0) L
W = -1.1 atm (2.5 L)
W = -2.75 atm L
Recall that:
1 atm L = 101.4 J
Therefore;
-2.75 atm L = ( -2.75 × 101.4 )J
= -278.85 J
Thus, the work required at the chemical reaction when the pressure applied is 1.1 atm = - 278.85 J
