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erica [24]
3 years ago
5

Help help help please , i will give brainliest

Physics
2 answers:
finlep [7]3 years ago
6 0

Answer:

I believe the answer for #1 is D and the answer for #2 is B

Explanation:

I hope this is correct and helps

butalik [34]3 years ago
4 0

Answer:

Explanation:

One

No one can answer the first question. We are not sure what a,b,c,d refer to. But I can tell you want to look for. If you complete the ray diagram shown, and you extend both the blue and red lines until they meet, they should meet to the left of the focus. The image is very large. Redraw the diagram so that you see what I am saying.

Make the object about a cm from the focus.

Make the focal length roughly 4 cm long.

Now make another drawing. Keep the focal distance from the lens about the same.

Make the object  about 1 cm from the lens.

Now put the two rays that you had from the original diagram.

  • You should find that the image is still virtual.
  • It is still right side up.
  • It is smaller than the image of the first diagram.
  • It is much closer to the object.
  • The image is between the object and   the left focus.

Two

You have the orange ray going to the lens. So far so good. Where it hits the lens, you should draw an orange line from that point to F2. That makes A the answer.

If you want to know where the image is, draw a line from the top of the object to the center of the lens.

The intersect point should be

  • to the right of the object and
  • to the left of lens.
  • The image is smaller than the object
  • virtual
  • rightside up.
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Accelerated motion such as a vehicle (car) or a moving item such as a (football thrown in the air)
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In which way does the popularity of modern sports help advance a society
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The popularity of modern sports help advance a society by bringing people together.
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3 years ago
"A short-wave radio antenna is supported by two guy wires, 150 ft and 170 ft long. Each wire is attached to the top of the anten
Nonamiya [84]

Answer:

The anchor points are 78.37 ft and 111.99 ft

Explanation:

If you look at the attached (Fig 1) you will find that the union of antenna and its guy wires forms two right triangles. To solve problems that involve this kind of triangles, you can apply trigonometric functions (sine, cosine, etc) and Pythagoras Theorem. Trigonometric functions states the relation between angles, sides and hypotenuse of a right triangle. If you look Fig2, considering α angle, "b" is the opposite side, "a" the adjacent side and "c" the hypotenuse. Then

a) Sine (α) = b/c it means opposite side/hypotenuse

b) Cosine (α)= a/c, it means adjacent side/hypotenuse

c) Tangent (α) = b/a opposite side/adjacent side.

Pythagoras theorem states that if you called "a" and "b", the sides of the right triangle, and "c" the hypotenuse, then:

                                      a² + b² = c²    

As the problem states the lengths 150 ft and 170 ft represents the value of the hypotenuse of each triangle and 65° is one of the angles of the triangle with 150 ft hypotenuse. So you can solve this using sin (65°) to find the height of the antenna (h) and then the two distances (x and y,).

Sine (65°) = h/ 150 ft ⇒ Sine (65°) x 150ft = h ⇒ h = 127.9 ft.

To find x : Cosine (65°) = x/ 150 ft ⇒ Cosine (65°) x 150 ft = x

⇒ x = 78.37 ft.

And finally, to find y we can apply Pythagoras theorem

(170 ft)² = (127.9 ft)² + y² ⇒ y² = (170 ft)² - (127.9 ft)² ⇒ y = 111.99 ft

Summarizing, the anchor points are 78.37 ft and 111.99 ft

4 0
3 years ago
A parallel-plate capacitor consists of plates of area 1.5 x 10^-4 m^2 separated by 2.0 mm The capacitor is connected to a 12-V b
Katen [24]

Answer:

4.78 x 10^-11 J

Explanation:

A = 1.5 x 10^-4 m^2

d = 2 mm = 2 x 10^-3 m

V = 12 V

Let C be the capacitance of the capacitor

C = ε0 A / d

C = (8.854 x 10^-12 x 1.5 x 10^-4) / (2 x 10^-3)

C = 6.64 x 10^-13 F

Energy stored, U = 1/2 CV^2

U = 0.5 x 6.64 x 10^-13 x 12 x 12

U = 4.78 x 10^-11 J

4 0
3 years ago
Hey nsnsnsndhdhd dudhshdhdh
PolarNik [594]

Answer:

hii

Explanation:

5 0
3 years ago
Read 2 more answers
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