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3 years ago

Help help help please , i will give brainliest

Physics

2 answers:

finlep [7]3 years ago

6 0

Answer:

I believe the answer for #1 is D and the answer for #2 is B

Explanation:

I hope this is correct and helps

butalik [34]3 years ago

4 0

Answer:

Explanation:

One

No one can answer the first question. We are not sure what a,b,c,d refer to. But I can tell you want to look for. If you complete the ray diagram shown, and you extend both the blue and red lines until they meet, they should meet to the left of the focus. The image is very large. Redraw the diagram so that you see what I am saying.

Make the object about a cm from the focus.

Make the focal length roughly 4 cm long.

Now make another drawing. Keep the focal distance from the lens about the same.

Make the object about 1 cm from the lens.

Now put the two rays that you had from the original diagram.

You should find that the image is still virtual.
It is still right side up.
It is smaller than the image of the first diagram.
It is much closer to the object.
The image is between the object and the left focus.

Two

You have the orange ray going to the lens. So far so good. Where it hits the lens, you should draw an orange line from that point to F2. That makes A the answer.

If you want to know where the image is, draw a line from the top of the object to the center of the lens.

The intersect point should be

to the right of the object and
to the left of lens.
The image is smaller than the object
virtual
rightside up.

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A 0.2 kg hockey puck moving at 80 m/s is caught by a 40 kg goalie at rest. With what speed does the goalie slide on the slide?

Lady_Fox [76]

Answer:

V = 0.39 m/s

Explanation:

Given that,

Mass of hockey puck, m = 0.2 kg

Mass of goalie = 40 kg

Speed of hockey puck, v = 80 m/s

We need to find the speed with which the goalie slide on the slide. Let V be the speed. Using the conservation of momentum as follows :

$mv=(M+m)V\\\\V=\dfrac{mv}{M+m}\\\\V=\dfrac{0.2\times 80}{0.2+40}\\\\V=0.39\ m/s$

So, the required speed is 0.39 m/s.

5 0

2 years ago

an object moving at 10. km/hr has a kinetic energy of 10. J. what is the kinetic energy of the same object if it is moving at 20

Schach [20]

Kinetic energy is related to velocity by:
KE = (1/2)mv^2

solve for mass m
10 = (1/2)m(10)^2
10 = (1/2)m(100)
10= 50m
10/50 = m
1/5 = m

at 20 km/hr

KE = (1/2)(1/5)(20)^2
KE = (1/10)(400)
KE = 40 J

5 0

3 years ago

Sound with a frequency of 1250 Hz leaves a room through a doorway with a width of 1.05 m.At what minimum angle relative to the c

kiruha [24]

Answer:

15.19°, 31.61°, 51.84°

Explanation:

We need to fin the angle for m=1,2,3

We know that the expression for wavelenght is,

$\lambda = \frac{c}{f}$