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3 years ago

PLEASE HELP GIVING BRAINLIEST ANSWER

1 answer:

7 0

Potential energy is an object’s stored energy when it is not moving. Kinetic energy is an object’s energy in motion. You can’t be both moving and not moving at the same time, so PE and KE cannot be equal.

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When you skid to a stop on your bike, you can significantly heat the small patch of tire that rubs against the road surface. Sup

Lunna [17]

Answer:

$E=14.4\ J$

Explanation:

In this case the kinetic energy of the bike is converted into the heat energy between the area of contact of tyre and the road. This happens due to the work done by the frictional force between the surface to stop the relative motion between the road and the tyre.

Given:

normal force on the rear tyre, $N=45\ N$

(as given in the question that the rear tyre supports half the combined weight of the bike and the rider.)

distance dragged while stopping the tyre, $s=0.4\ m$

coefficient of kinetic friction between the surfaces, $\mu=0.8$

Now, frictional force between the surfaces:

$f=\mu.N$

$f=0.8\times 45$

$f=36\ N$

Now, the work done by the kinetic friction:

$W=f.s$

$W=36\times 0.4$

$W=14.4\ J$

According to the energy conservation this amount of energy is converted into thermal energy between the surfaces in contact, i.e. road and the tyre.

5 0

3 years ago

How much heat is needed to raise the temperature of 100 g of water by 50 C, if the specific heat of water is 4,184 J/kg.C?

Yuliya22 [10]

Heat required to raise the temperature of water is given as

$Q = ms\Delta T$

here we have

m = 100 g = 0.100 kg

s = 4183 J/kg C

$\Delta T = 50 ^0 C$

now we can use the above equation

$Q = 0.100 * 4184 * 50$

$Q = 20920 J$

so here it requires 20920 J heat to raise the temperature of 100 g water by 50 degree C

4 0

3 years ago

Light of wavelength 648.0 nm is incident on a narrow slit. The diffraction pattern is viewed on a screen 57.5 cm from the slit.

boyakko [2]

Answer:

$71.0 \mu m$

Explanation:

The formula for the single-slit diffraction is

$y=\frac{n\lambda D}{d}$

where

y is the distance of the n-minimum from the centre of the diffraction pattern

D is the distance of the screen from the slit

d is the width of the slit

$\lambda$ is the wavelength of the light

In this problem,

$\lambda=648.0 nm=6.48\cdot 10^{-7}m$

$D=57.5 cm=0.575 m$

$y=1.05 cm=0.0105 m$ , with n=2 (this is the distance of the 2nd-order minimum from the central maximum)

Solving the formula for d, we find:

$d=\frac{n\lambda D}{y}=\frac{2(6.48\cdot 10^{-7} m)(0.575 m)}{0.0105 m}=7.10\cdot 10^{-5} m= 71.0 \mu m$

6 0

3 years ago

A mother is helping her children, of unequal weight, to balance on a seesaw so that they will be able to make it tilt back and f

horsena [70]

Answer:

L₁ = W×L / w

Explanation:

The scenario is shown in the image below.

At the pivot point, the torque acting on this point must be zero so that there will be easy back and forth without the heavier child.

Torque created by lighter child + Torque created by the heavier child = 0

Thus,

According to the axis system, the heavier child is left to the pivot (origin), so,

W×(- L ) + w× L₁ = 0

So,

L₁ = W×L / w

7 0

4 years ago

Robin is standing terrified at the end of a diving board, which is high above the water. If Robin has a mass of 76 kg and is sta

masya89 [10]

Answer:

Torque = 1191.68 N-m

Explanation:

Given data

mass m = 76 kg

standingdistance r = 1.6 m

Solution

we get here torque that si express as

torque = force × distance ................1

torque = r × F sin(theta)

and we know that

F = mg .........2

and g = 9.8 m/s²

put here value in equation 1 we get

Torque = 76 × 1.6 × 9.8 × sin(90)

Torque = 1191.68 N-m

5 0

3 years ago