Here we have to calculate the number of moles of valuable propane can be prepared from 1.8 moles of carbon.
From 1.8 moles of carbon 0.3 moles of propane can be prepared by the reaction.
From 6 moles of carbon (C) 1 moles of valuable propane (C₃H₈) can be prepared.
Thus from 1.8 moles of C we can obtain ×1.8 = 0.3 moles of the propane can be prepared.
Thus the amount of propane produced in this reaction is determined.
Volume of hydrogen at STP = moles x 22.4 = 7x22.4 = 156.8L
<u>Answer:</u>
<em>The final volume must be 400 mL.</em>
<em></em>
<u>Explanation:</u>
Let us assume the Initial volume as 100ml
Using dilution factor formula
So,
Thus, the final volume must be 400 mL.
Answer:
equal to the number of neutrons
Answer:
hydrogen bonding among water molecules
Explanation: