What is the formula for P₃O₅?

In this experiment, 0.070 g of caffeine is dissolved in 4.0 ml of water. The caffeine is then extracted from the aqueous solutio

Damm [24]

2.0ml of methylene chloride solution is used each time to extract caffeine from the aqueous solution.

Consider the concentration of caffeine obtained during each individual extraction from the aqueous solution to be C.

The total amount of caffeine obtained during each extraction is calculated as

(Total volume of water used to make up the caffeine aqueous solution) x (concentration of caffeine obtained during each individual extraction from the aqueous solution) + (Volume of methylene chloride added during each extraction x distribution coefficient of caffeine x concentration of caffeine obtained during each individual extraction from the aqueous solution)

Substituting these values we get

The total amount of caffeine obtained during each extraction

= (4.0×C )+ (2.0×4.6 × C)

= 13.2 C

The amount of caffeine remaining in the aqueous solution is calculated as

(Total volume of water used to make up the caffeine aqueous solution) x (concentration of caffeine obtained during each individual extraction from the aqueous solution)

Substituting these values we get

The amount of caffeine remaining in the aqueous solution = 4 × C

The fraction of caffeine remaining in aqueous solution is calculated as

= (The total amount of caffeine obtained during each extraction)/ (The amount of caffeine remaining in the aqueous solution)

=4.0 C/13.2 C

= 1/3.3.

Therefore the fraction of caffeine left in aqueous solution after 3 extractions is =(1/3.3)^3 =0.028

Therefore, the total amount of caffeine extracted

=0.070 × (1-(1/3.3)^3)

= 0.068 g

5 0

3 years ago

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At one point in your life, you might have played on a swing. Have you ever wondered why, after the first swing, it will slow dow

cestrela7 [59]

Answer:

at the top of the swing

at the bottom of the swing

Explanation:

7 0

3 years ago

In which cell organelle does protein synthesis occur? cytoplasm mitochondria ribosome cell membrane

MariettaO [177]

It occurs in The ribosome

8 0

3 years ago

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What is the new pressure of 150 mL of a gas that is compressed to 50 mL when the original pressure was 3.0 ATM and the temperatu

Arisa [49]

Answer:

$\boxed {\boxed {\sf P_2= 9 \ atm}}$

Explanation:

Since the temperature is held constant, we only need to focus on the volume and pressure. We will use Boyle's Law, which states the volume of a gas is inversely proportional to the pressure. The formula is:

$P_1V_1=P_2V_2$

Originally, the gas had a volume of 150 milliliters and a pressure of 3.0 atmospheres. We can substitute these values into the left side of the equation.

$3.0 \ atm * 150 \ mL = P_2V_2$

The original gas was compressed to a volume of 50 milliliters, but we don't know the volume.

$3.0 \ atm *150 \ mL= P_2 * 50 \ mL$

Now, we need to solve for the new pressure (P₂). Multiply on the left side first.

$450 \ atm*mL= P_2 * 50 \ mL$

Since we are solving for the pressure, we need to isolate the variable. It is being multiplied by 50 mL. The inverse of multiplication is division. Divide both sides by 50 mL.

$\frac{450 \ atm*mL}{50 \ mL}= \frac{P_2 * 50 \ mL}{50 \ mL}$

$\frac{450 \ atm*mL}{50 \ mL}= P_2$

The units of milliliters will cancel.

$\frac{450 \ atm}{50 }= P_2$

$9 \ atm =P_2$

The new pressure is <u>9 atmospheres.</u>

8 0

3 years ago

Can i get a snap i could send a link to, to do a few chem 1 assignments i could award more points

Colt1911 [192]

Answer:The FitnessGram PACER Test is a multistage aerobic capacity test that progressively gets more difficult as it continues. The test is used to measure a student's aerobic capacity as part of the FitnessGram assessment. Students run back and forth as many times as they can, each lap signaled by a beep sound.

Explanation:

4 0

3 years ago