Answer:
the minimum value of the coefficient of static friction between the ground and the cheetah's feet is 1.94
Explanation:
Given that ;
the top speed of Cheetahs is almost 60 mph
In cornering abilities ; the maximum centripetal acceleration of a cheetah was measured to be = 19 m/s^2
The objective of this question is to determine the what minimum value of the coefficient of static friction between the ground and the cheetah's feet is necessary to provide this acceleration?
From the knowledge of Newton's Law;
we knew that ;
Force F = mass m × acceleration a
Also;
The net force = frictional force
so we can say that;
m×a =
where;
the coefficient of static friction is:
= 1.94
Hence; the minimum value of the coefficient of static friction between the ground and the cheetah's feet is 1.94
Answer:
b
Explanation:
acceleration is directly proportional to the net force and inversely proportional to the mass
Answer:
a)this graph is also a line b) in both cases we have a uniform movement
Explanation:
In this exercise we have a uniform movement
v = d / t
d = v t
in the table we give some values to make the graph
t (s) d (m)
1 10
2 20
3 30
In the attached we can see the graph that is a straight line
we have another vehicle at v = 50 me / S
t (s) d (m)
1 50
2 100
3 150
this graph is also a line
b) in both cases we have a uniform movement
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