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Serhud [2]
3 years ago
10

Which of the following objects is exerting a gravitational force on the floating tool? the Earth, the Moon, the astronaut, the S

un
Physics
2 answers:
Tcecarenko [31]3 years ago
4 0
All of them are correct.
Norma-Jean [14]3 years ago
3 0

Answer:

<em>All of them</em>

Explanation:

<em>Hope this helps!</em>

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Two trains are on separate but parallel tracks running east and west. One has a speed of 90 km/h, the other 80 km/h. Initially,
Tanzania [10]

Answer: 4 hours

Explanation: Their approach rate is 100+140 or 240 km/h and 960/240 which equals 4 hours

4 0
4 years ago
The force that attracts earth to an object is equal to and opposite the force that earth exerts on the object. Explain why earth
alexandr402 [8]

Answer:

Because of heavy mass

Explanation:

When force acts on a body it tends to accelerate the body. The acceleration produced in the body depends on two things:

1). Magnitude of force

2). Mass of the body

F= ma

⇒ a = F/m  

As the force exerted on earth and another object are the equal in magnitude but opposite in direction. This forces will accelerate the object toward the earth but can't accelerate the earth as earth has very high mass.

a = F/m

This force tends to accelerate the earth but but due to earth's inertia the earth does not accelerate.

7 0
3 years ago
The force required to drag several objects across a floor was measured. Calculate the µK for these objects.
olganol [36]

Answer:

Explanation:

Case-A

Block weight W=150\ lb

Friction Force f=30\ lb

and friction force is

f=\mu _kN

where N=normal reaction (Usually equals to weight)

\mu _k=\frac{30}{150}

\mu _K=\frac{1}{5}=0.2

Case-B

Block weight W=20\ N

Friction Force f=5\ N

\mu _k=\frac{f}{N}

\mu _k=\frac{5}{20}=\frac{1}{4}

\mu _k=0.25

Case-C

Block weight W=1500\ lb

Friction Force f=60\ lb

\mu _k=\frac{f}{N}

\mu _k=\frac{60}{1500}

\mu _k=0.04

4 0
4 years ago
A na+ ion moves from inside a cell, where the electric potential is -72 mv, to outside the cell, where the potential is 0 v. wha
Vlada [557]
The change in electric potential energy of the ion is equal to the charge multiplied by the voltage difference:
\Delta U = q \Delta V = q (V_f - V_i)
where the charge q of the na+ ion is equal to one positive charge, so it's equal to the proton charge: q=1.6 \cdot 10^{-19} C, and Vf and Vi are the final and initial voltages.

Substituting the numbers, we find:
\Delta U = (1.6 \cdot 10^{-19}C)(0 V-(-0.072 V))=1.15 \cdot 10^{-20} J
7 0
3 years ago
Read 2 more answers
In a clock, the average speed is maximum for the tip of
seraphim [82]
The answer is A) seconds hand
7 0
3 years ago
Read 2 more answers
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