Answer:
Explanation:
Hello,
In this case, given the reaction, we can directly compute the theoretically yielded grams of carbon dioxide, considering the 2:2 molar ratio between carbon monoxide (molar mass = 28 g/mol) and carbon dioxide (molar mass = 44 g/mol) and the initial reacting grams of carbon monoxide in excess oxygen:
Thus, as only 8 g were actually yielded, we compute the percent yield:
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Greetings!
<h3>To find the empirical formula you need the relative atomic mass of each element!</h3>
N = 14
H = 1
S = 32.1
<h3>You can simply change the percentages into full grams</h3>
N = 12.20
H = 6.06
S = 48.45
<h3>Then you use this to find the Number of moles = amount in grams / atomic mass</h3>
N = 12.20 ÷ 14 = 0.8714
H = 6.06 ÷ 1 = 6.06
S = 48.45 ÷ 32.1 = 1.541
<h3>Then divide each number of moles by the smallest value:</h3>
N = 0.8714 ÷ 0.8714 = 1
H = 6.06 ÷ 0.8714 = 6.9 ≈ 7
S = 1.541 ÷ 0.8714 = 1.76 ≈ 2
So that means that there are 1 Nitrogen, 7 hydrogen, and 2 sulfur. This means the empirical formula would be:
NH₇S₂
Hope this helps!
Here is the answer
http://m.imgur.com/tJ2WwiN
A practical pursuit of alchemy was the development of metallurgy practices. As alchemists always tried to turn various metals into other things, metalworking techniques were developed even though their experiments were often unsuccessful.
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