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meriva
3 years ago
5

The elements in yellow are referred to as ___________.

Chemistry
1 answer:
Lemur [1.5K]3 years ago
8 0

Answer:

Metalloids

Explanation:

hope this helps! :)

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The Sun has six regions or layers. Identify the Sun's layers, beginning with the innermost and moving out.
balu736 [363]

Answer:

Beginning from the innermost layer and moving towards the outermost of the sun that has six layers.

1. Innermost layer is the core: All the energy of the sun comes from core. Here hydrogen and helium are components that are present.

2. Radiative zone: The high-energy photons are move from the innermost core to the second innermost radiative zone.

3. Convective zone: It is a comparatively cooler layer to the core and radiative zone.

4. Photosphere: It is the 4th innermost region with sunspots and called the magnetic field of the sun.

5. Chromosphere: This red color layer with filaments of gas is cooler than the photosphere.

6. Corona: It is the outermost layer of the sun and the temperature is much higher here.

4 0
3 years ago
Are natural gas, oil and coal are all considered to be fossil fuels?
DedPeter [7]

Answer: The answer is Yes, because they were formed from the remains of plants and animals from millions of years ago.

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3 years ago
Shane performed the following trials in an experiment. Trial 1: Heat 30.0 grams of water at 0 °C to a final temperature of 40.0
Strike441 [17]

Answer:

A. The same amount of heat is absorbed in both the experiments because the product of mass, specific heat capacity, and change in temperature are equal for both.

Explanation:

  • The amount of heat absorbed by water (Q) can be calculated from the relation:

<em>Q = m.c.ΔT.</em>

where, Q is the amount of heat absorbed by water,

m is the mass of water,

c is the specific heat capacity of water (c = 4.186 J/g °C),

ΔT is the temperature difference (final T - initial T).

  • <u><em>For trial 1:</em></u>

m = 30.0 g, c = 4.18 J/g °C, ΔT = 40.0 °C – 0.0 °C = 40.0 °C

<em>∴ Q = m.c.ΔT</em> = (30.0 g)(4.18 J/g °C)(40.0 °C) = <em>5023 J.</em>

  • <u><em>For trial 2:</em></u>

m = 40.0 g, c = 4.18 J/g °C, ΔT = 40.0 °C – 10.0 °C = 30.0 °C

<em>∴ Q = m.c.ΔT</em> = (40.0 g)(4.18 J/g °C)(30.0 °C) = <em>5023 J.</em>

  • So, the right choice is:

<em>A. The same amount of heat is absorbed in both the experiments because the product of mass, specific heat capacity, and change in temperature are equal for both. </em>

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