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fredd [130]
3 years ago
6

Susannah is buying lunch for her friends at a restaurant. The bill is $50, and she wants to

Mathematics
1 answer:
valentinak56 [21]3 years ago
3 0

Answer:

she tips $9

Step-by-step explanation:

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True or false????????????
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False for every rate there is only one unit rate. there is however more than 1 rates for one unit rate. for example 4/2 would have 2/1 as a unit rate but 2/1 can have 4/2 and 8/4 as rates and so on. hope this helps good luck!
8 0
4 years ago
Simplify the expression. 12x^-6 y^10 times 3x^7 y
Vlada [557]

We need to simplify the expression:

12x^{-6}y^{10} \times (3x^{7}y)

Now, we know that we can resolve the exponents of the variables with the like terms only and we can multiply the coefficients independently:

Now,  

12x^{-6}y^{10} \times 3x^{7}y=(12 \times 3)\times (x^{-6}\times x^{7})\times (y^{10}\times y)

On simplifying the above expression we get:

36\times x^{(-6+7)}\times y^{(10+1)}

=36 \times x^{1}\times y^{11}

=36 \times x \times y^{11}

=36xy^{11}

So the simplified form of the expression 12x^{-6}y^{10} \times 3x^{7}y=36xy^{11}.

7 0
3 years ago
(2+x)dy/dx=3y need help
den301095 [7]
(2+x) \frac{dy}{dx} =3y
\frac{1}{3y} dy= \frac{1}{2+x} dx
\int { \frac{1}{3y} } \, dy = \int { \frac{1}{2+x} } \, dx
\frac{1}{3}\ln(3y) = \ln(2+x) + C
(raise both to the power e): e^{ \frac{1}{3}\ln(3y)}=e^{\ln(k(2+x))}
(3y)^ \frac{1}{3} =k(2+x)
3y=k(2+x)^3
y= k(2+x)^3
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3 years ago
This is for the person thats been helping me thanks (:
sergeinik [125]

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7 0
3 years ago
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Simplify this equation...
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